Answer:
<u><em>Energy:</em></u> <em>It is the capacity of work done by the body, </em>
- <em>for example, kinetic energy, potential energy, thermal energy, and so on. The S.I. unit of energy is Joule.</em>
<u>Mechanical Energy: </u><em>Mechanical energy is the energy of the body corresponding to its motion or change in its position. </em>
- <em>For example, potential energy and kinetic energy.</em>
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<u><em>Law of conservation of energy: </em></u><em>According to the law of conservation of energy, the net energy of the system remains conserved.</em>
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- <em>For example, in the case of elastic collision, the net energy of the system is conserved before and after the collision.</em>
<u><em></em></u>
<u><em>Law of conservation of energy for moving object: </em></u><em>The net energy of the moving object remains conserved.</em>
<em />
- <em>For example, the net energy of the ball sliding down the hill without any loss of energy remain conserved.</em>
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<em></em>
Answer:
Fundamental frequency= 174.5 hz
Explanation:
We know
fundamental frequency=![\frac{velocity}{2 *length}](https://tex.z-dn.net/?f=%5Cfrac%7Bvelocity%7D%7B2%20%2Alength%7D)
velocity =![\sqrt{\frac{tension}{mass per unit length} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7Btension%7D%7Bmass%20per%20unit%20length%7D%20%7D)
mass per unit length=
=0.00427![\frac{kg}{m}](https://tex.z-dn.net/?f=%5Cfrac%7Bkg%7D%7Bm%7D)
Now calculating velocity v=![\sqrt{\frac{255}{0.00427} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B255%7D%7B0.00427%7D%20%7D)
=244.3![\frac{m}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%7D%7Bsec%7D)
Distance between two nodes is 0.7 m.
Plugging these values into to calculate frequency
f =
=174.5 hz
Answer:
![@=17.32^{\circ}](https://tex.z-dn.net/?f=%40%3D17.32%5E%7B%5Ccirc%7D)
Explanation:
It is given that,
Radius of the banked road, r = 400 m
Speed of the car for the safe travelling, v = 35 m/s
On the banking of a curve, the force of friction is balanced by the centripetal force acting on it such that the banking angle is given by :
![tan@=\dfrac{v^2}{rg}](https://tex.z-dn.net/?f=tan%40%3D%5Cdfrac%7Bv%5E2%7D%7Brg%7D)
![tan@=\dfrac{(35\ m/s)^2}{400\ m\times 9.8\ m/s^2}](https://tex.z-dn.net/?f=tan%40%3D%5Cdfrac%7B%2835%5C%20m%2Fs%29%5E2%7D%7B400%5C%20m%5Ctimes%209.8%5C%20m%2Fs%5E2%7D)
![tan@=0.312](https://tex.z-dn.net/?f=tan%40%3D0.312)
![@=17.32^{\circ}](https://tex.z-dn.net/?f=%40%3D17.32%5E%7B%5Ccirc%7D)
So, the banking angle of the road is 17.32 degrees. Hence, this is the required solution.
Answer:
question 1 is centripetal acceleration question 2 is 4
Explanation:
centripetal acceleration basically is acceleration that only changes velocity but not speed, while for question 2, you divide 10 by 2.5