A bowling ball is pushed with a force of 22.0N and accerlates at 5.5 m/s square. What is the mass of the bowling ball

what causes places near the equator to receive more direct sunlight than the poles? the poles are farther away from the sun than

Andru [333]

This is due to the tilt of the earth on its axis. Although the Sun shines on Earth, because of how the Earth is tilted, the equator is more directly hit compared to places found on the poles. The poles are hit at an angle, therefore the sunlight they receive is lesser than the places at the equator.

5 0

2 years ago

if an object is being acted on by two forces a push and a pull of 6N what is the net force of the object

Paul [167]

The concepts of force, mass, and weight play critical roles. Newton's Laws of. Motion ... the person stops pushing? ... F net =10 N 2 N. = 8 N (to the right) a = F net m. = 8 N. 5 kg. =1.6 m s. 2 ... Two equal forces act on an object in the directions shown. If these ... Two connected carts being accelerated by a force F applied by.

6 0

2 years ago

A 30-km, 34.5-kV, 60-Hz, three-phase line has a positive-sequence series impedance z 5 0.19 1 j0.34 V/km. The load at the receiv

zmey [24]

Answer:

(a) With a short line, the A,B,C,D parameters are:

A = 1pu B = 1.685∠60.8°Ω C = 0 S D = 1 pu

(b) The sending-end voltage for 0.9 lagging power factor is 35.96 $KV_{LL}$

(c) The sending-end voltage for 0.9 leading power factor is 33.40 $KV_{LL}$

Explanation:

(a)

Considering the short transition line diagram.

Apply kirchoff's voltage law to the short transmission line.

Write the equation showing the relations between the sending end and the receiving end quantities.

Compare the line equations with the A,B,C,D parameter equations.

(b)

Determine the receiving-end current for 0.9 lagging power factor.

Determine the line-to-neutral receiving end voltage.

Determine the sending end voltage of the short transition line.

Determine the line-to-line sending end voltage which is the sending end voltage.

(c)

Determine the receiving-end current for 0.9 leading power factor.

Determine the sending-end voltage of the short transition line.

Determine the line-to-line sending end voltage which is the sending end voltage.

8 0

3 years ago

malcom is doing a wheely on his motorcycle and moving at 20 m/s with a momentum of 6000 kg m/s when he lays her down. The mass o

rodikova [14]

Answer:

110 kg

Explanation:

The momentum of the Malcom+motorcycle system is given by:

$p=(m+M)v$

where

(m+M) is the total mass of the system, with

m = mass of Malcom

M = 190 kg (mass of the motorcycle)

v = 20 m/s velocity

Since we know the momentum:

p = 6000 kg m/s

We can re-arrange the equation to find the mass of Malcom:

$m=\frac{p}{v}-M=\frac{6000 kg m/s}{20 m/s}-190 kg=110 kg$

3 0

3 years ago

Find the magnitude of the torque produced by a 4.8 N force applied to a door at a perpendicular distance of 0.43 m from the hing

SVEN [57.7K]

Answer:

2.064 N.m

Explanation:

Torque: This is the force that act on a system, which tends to cause rotation or twisting. The S.I unit of Torque is N.m

Torque is represented mathematically as,

T = F×d........................ Equation 1

Where T = Torque, F = Force, d = perpendicular distance.

Given: F = 4.8 N, d = 0.43 m.

Substitute into equation 1

T = 4.8×0.43

T = 2.064 N.m

Hence the Torque produced = 2.064 N.m

6 0

3 years ago