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3 years ago

Find the mass if the force is 18 n and the acceleration is 2 m/s/s

Physics

1 answer:

Mazyrski [523]3 years ago

4 0

Answer:

<h2>The answer is 9 kg</h2>

Explanation:

The mass of an object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{18}{2} \\$

We have the final answer as

Hope this helps you

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8. A student does 1,000 J of work when she moves to her dormitory. Her internal energy is decreased by 3,000 J. Determine the he

Lyrx [107]

Answer:

The heat loss during the process = -4000 J

Explanation:

Work done by the student (W) = - 1000 J

Negative sign on the system is due to work done on the system.

Decrease in internal energy (U) = - 3000 J

We know that heat transfer in the system is given by (Q) = U + W

⇒ Q = - 1000 - 3000

⇒ Q = - 4000 J

This is the value of heat transfer during the process And negative sign indicates that heat loss during the process.

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3 years ago

romanna [79]

Answer:HERE IS YOUR ANSWER

THE POINTS ARE

IF WE PUT THE OBJECT BETWEEN THE FOCUS

AND THE POLE

THEN THE IMAGE FORMED WILL be MAGNIFIED

If that’s not what you are looking for, try this one:

For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.

Given here the "size of the image" is twice to that of the object.

Hence, it is consider that the magnification is +2.

So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."

Explanation:

3 0

3 years ago

Read 2 more answers

Kieran takes off from rest down a 50 m high, 10° slope on his jet-powered skis. The skis have a thrust of 280 N parallel to the

xz_007 [3.2K]

Answer:0.46

Explanation:

Given

Initial height $h=50 m$

inclination $\theta =10^{\circ}$

Thrust $=280 N$

combined mass of kieran and skis $m=50 kg$

Speed at the bottom $v=40 m/s$

From Work Energy Theorem

Work done by all the force is equal to change in kinetic Energy

$W_{gravity}+W_{friction}+W_{thrust}=\frac{1}{2}mv^2-0$ ------------1

distance traveled along the slope $x=\frac{50}{\sin 10}=287.93 m$

$W_{gravity}=mgh=50\times 9.8\times 50=24500 J$

$W_{thrust}=F\times x=280\times 287.93=80,620.4 J$

$W_{friction}=-\mu mg\cos 10$

substitute in 1

$24,500+80,620.4+W_{friction}=\frac{1}{2}\times 50\times 1600$

$W_{friction}=40,000-24,500-80,620.4$

$-\mu \cdot 50\times 9.8\times 287.93=-65,120.4$

$\mu =\frac{65,120.4}{141,085.7}=0.46$

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3 years ago

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m_a_m_a [10]

Answer:

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