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garri49 [273]
3 years ago
7

Two objects are attracted to each other by electromagnetic forces. Suppose I double the charge of one object. How can I return t

he force to its original value?
Physics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

1. Reduce the charge on second object by half or

2. Increase the distance between the two charges by a factor of 1.41 (√2).

Explanation:

Lets assume,

Charge on first object = Q

Charge on second object = q

Distance between them = r

Force between the two charges = F

According to Coulomb's law,

F = k \frac{Qq}{r^{2}}

where, k = Coulomb constant

New value of charge on first object = 2Q. Thus the new force(F') will be

F' = k \frac{2Qq}{r^{2}}

F' = 2F

So, to bring the value of force(F') to original value, there are two options:

1. Reduce the charge on second object by half or

2. Increase the distance between the two charges by a factor of 1.41 (√2).

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Answer:
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The magnitude of vector b is 91.92 m
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\displaystyle{x_B = v_B\cdot t= 20 \cdot 2 = 40\ nmi

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