Answer:
The number of moles of HCl in the 250 mL volumetric flask is 0.003 moles
Explanation:
Firstly, we solve for the concentration of acid using the formula
CaVa/CbVb = nₐ/nb
where Ca is the concentration of acid
Cb is the concentration of base
Va is the volume of acid
Vb is the volume of base
nₐ is the number of moles of acid (from the equation)
nb is the number of moles of base (from the equation)
Ca × 250/0.09876 × 29.59 = 1/1
Ca = 0.09876 × 29.59/250
Ca = 0.012 M
To determine the number of moles of HCl acid present in the 250 ml volumetric flask, the formula for molarity is used
Molarity = number of moles ÷ volume (in liter or dm³)
Volume needs to be converted to liter; 250 ml ⇒ 0.25 L
Molarity of the acid is 0.012 M
From the formula above, number of moles = molarity × volume (in liter)
number of moles = 0.012 × 0.25
number of moles of acid = 0.003 moles
Answer:
B. When it is obtained by rounding, as in 3.0
Explanation:
Potassium Iodide have a lot of strong bonds which requires a very high temperature (high energy) to break them and change into a different state of matter.
Answer: The concentration of Silver Nitrate in solution # 4 is 3.5x10-6 M
Explanation:
When calculating the concentration of a dilute solution, we use the equation:
C1V1 = C2V2
Where C1 = concentration of the known solution
V1= amount of know solution
C2= new concentration
V2= capacity of the flask
Keep in mind that solution #2 is not related to the preparation of solutions #3 y #4, so the concentration of #2 is irrelevant.
For calculating the concentration of solution #4 , we first calculate the concentration of the solution #3, that comes from the solution #1.
- Calculating concentration solution #3
- C1V1 = C3V3
- C3= (0.0002442 M * 10mL) / 250mL
- C3= 9.8X10-6M
2. Calculating concentration solution #4
- C3V3 = C4V4
- C4= (9.8X10-6M *18mL) / 50mL
- C4= 3.5X10-6 M