The outside of most foods turn green because of mold after a period of time it had been left out including cheese
I think it's letter:
B.Coefficients are placed in front of the reactants and/or products
Answer:
Polonium: <em>Number</em><em> </em><em>of</em><em> </em><em>protons</em><em> </em><em>=</em><em> </em><em>8</em><em>2</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Number</em><em> </em><em>of</em><em> </em><em>neutrons</em><em> </em><em>=</em><em> </em><em>2</em><em>0</em><em>6</em>
Sodium: <em>Number</em><em> </em><em>of</em><em> </em><em>protons</em><em> </em><em>=</em><em> </em><em>1</em><em>1</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Number</em><em> </em><em>of</em><em> </em><em>neut</em><em>rons</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em>
Answer:
![r=25M^{-1}s^{-1}[A]^2](https://tex.z-dn.net/?f=r%3D25M%5E%7B-1%7Ds%5E%7B-1%7D%5BA%5D%5E2)
Explanation:
Hello there!
In this case, according to the given information for this chemical reaction, it is possible for us to set up the following general rate law and the ratio of the initial and the final (doubled concentration) condition:
![r=k[A]^n\\\\\frac{r_1}{r_2} =\frac{k[A]_1^n}{k[A]_2^n}](https://tex.z-dn.net/?f=r%3Dk%5BA%5D%5En%5C%5C%5C%5C%5Cfrac%7Br_1%7D%7Br_2%7D%20%3D%5Cfrac%7Bk%5BA%5D_1%5En%7D%7Bk%5BA%5D_2%5En%7D)
Next, we plug in the given concentrations of A, 0.2M and 0.4 M, the rates, 1.0 M/s and 4.0 M/s and cancel out the rate constants as they are the same, in order to obtain the following:
Which means this reaction is second-order with respect to A. Finally, we calculate the rate constant by using n, [A] and r, to obtain:
![k=\frac{r}{[A]^n} =\frac{1.0M/s}{(0.2M)^2}\\\\k=25M^{-1}s^{-1}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7Br%7D%7B%5BA%5D%5En%7D%20%3D%5Cfrac%7B1.0M%2Fs%7D%7B%280.2M%29%5E2%7D%5C%5C%5C%5Ck%3D25M%5E%7B-1%7Ds%5E%7B-1%7D)
Thus, the rate law turns out to be:
Regards!
Answer: 39.948
Explanation:
How many grams Argon in 1 mol? The answer is 39.948. We assume you are converting between grams Argon and mole. You can view more details on each measurement unit: molecular weight of Argon or mol The molecular formula for Argon is Ar.
