Answer:
<em>Part A </em>C = (10,5)<em> Part B </em>C. D'(0,10)
Step-by-step explanation:
<em>Part A</em>
Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5
(2,1) * 5 = (10,5)
The new point C is going to be (10,5)
<em>Part B</em>
If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from <em>the origin</em> by 5.
In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)
Answer:
What was this for ?
Step-by-step explanation:
Answer:
students in the drama club: 57
students in the yearbook club: 44
Step-by-step explanation:
101 - 13 = 88
88 / 2 = 44
101 - 44 = 57
44 in the drama club and 57 in the yearbook club
Answer: FALSE.
Step-by-step explanation:
Given the following equation provided in the exercise:

You need to solve for the variable "x".
In order to solve for "x" you can folllow the steps shown below:
1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

Therefore, as you can observe, the given equation has no solutions.
Answer:
a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
b) 
a.15
c) For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:

Step-by-step explanation:
Part a
For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

d.9
Part b
From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

And the sample variance for this case can be calculated from this formula:

a.15
Part c
For this case we have the sample size n = 25 and the sample variance is
, the standard error can founded with this formula:
