Answer:
Brother is 70.5 and sister is 64.5
Step-by-step explanation:
you will need to set up a simple equation and give out variables.
Girls age = 6-x
Brother's age= x
the you will take those 2 and add them and place them equal to 135:
6-x+x=135
6-2x+6=135+6
The 6 cancels out
2x=141
2x/2=141/2
x=70.5
The brother's age would be 70.5 then and the girl's would be 64.5
What they said^ lolllllllllll
Answer:
Step-by-step explanation:
We want to find the inverse of
![y = \sqrt[3]{ \frac{x}{3} + 1}](https://tex.z-dn.net/?f=%20y%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7Bx%7D%7B3%7D%20%2B%201%7D%20)
We interchange x and y to get:
![x= \sqrt[3]{ \frac{y}{3} + 1}](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%7D%7B3%7D%20%2B%201%7D%20)
We solve for y;
Multiply through by 3
Subtract 1 from both sides:
Therefore the inverse is
Answer:
(x2 , y2) = (22,50)
Step-by-step explanation:
Given:
m1 : m2 = 1:4
(x1 , y1) = (7 , 5)
(X ,Y) = (10 ,14)
Find:
(x2 , y2)
Computation:
X = (m1x2 + m2x1) / (m1+m2)
10 = [(1)(x2) + (4)(7)]/(1+4)
10 = [x2 + 28]/5
22 = x2
Y = (m1y2 + m2y1) / (m1+m2)
14 = [(1)(y2) + (4)(5)]/(1+4)
14 = [y2 + 20]/5
70 = y2 + 20
50 = y2
(x2 , y2) = (22,50)
Answer: √51
—————————
a^2 + b^2 = c^2
a^2 + 7^2 = 10^2
a^2 + 49 = 100
a^2 = 51
√(a^2) = √51
a = √51
