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Amanda [17]
3 years ago
7

How are exponential functions related to logarithmic functions? Model that with an example.

Mathematics
1 answer:
scoundrel [369]3 years ago
3 0
Exponential functions are related to logarithmic functions in that they are inverse functions. Exponential functions move quickly up towards a [y] infinity, bounded by a vertical asymptote (aka limit), whereas logarithmic functions start quick but then taper out towards an [x] infinity, bounded by a horizontal asymptote (aka limit).
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
{e}^{y}  = x
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
{e}^{y}  = x
switch the x and y, then solve for y:
{e}^{x}  = y
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
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How does the graph of g(x)=1/x-5. +2 compare to the graph of the parent function f(x)=1/x
malfutka [58]

Answer:

x value of vertical asymptote and y value of horizontal asymptote

Step-by-step explanation:

The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)

As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)

Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?

When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5

What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0

What y value does g(x) approach as x gets bigger?  Well, as x gets big, 1/(x-5) gets small, approaching 0.  The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote

8 0
3 years ago
(1 point) Find y as a function of x if
Alenkasestr [34]
Y’’(x)= 6x + 1
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7 0
1 year ago
find the probability of being delt 5 clubs and 3 cards with one of each remaining suit in 8 card poker
kumpel [21]

Answer: 0.003757(approx).

Step-by-step explanation:

Total number of combinations of selecting r things out of n things is given by:-

^nC_r=\dfrac{n!}{r!(n-r)!}

Total cards in a deck = 52

Total number of ways of choosing 8 cards out of 52 = ^{52}C_8

Total number of ways to choose 5 clubs and 3 cards with one of each remaining suit = ^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1  [since 1 suit has 13 cards]

The required probability = =\dfrac{^{13}C_5\times^{13}C_1\times^{13}C_1\times^{13}C_1}{^{52}C_8}

=\dfrac{\dfrac{13!}{5!8!}\times13\times13\times13}{\dfrac{52!}{8!44!}}\\\\=\dfrac{24167}{6431950}\\\\\approx0.003757

Hence, the required probability is 0.003757 (approx).

5 0
3 years ago
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alina1380 [7]
I don’t know but you can go download Conects. :)
7 0
3 years ago
Evaluate 0 × |-6|. ......
kupik [55]

Answer:

0

Step-by-step explanation:

Any value multiplied by zero equals zero , thus

0 × | - 6 | = 0

6 0
3 years ago
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