How are exponential functions related to logarithmic functions? Model that with an example.
1 answer:
Exponential functions are related to logarithmic functions in that they are inverse functions. Exponential functions move quickly up towards a [y] infinity, bounded by a vertical asymptote (aka limit), whereas logarithmic functions start quick but then taper out towards an [x] infinity, bounded by a horizontal asymptote (aka limit).
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
switch the x and y, then solve for y:
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
switch the x and y, then solve for y:
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
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Answer:
Step-by-step explanation:
1) Mark two points on the line in the graph.
2) Determine the rise and run. Rise ---> difference in y-coordinates. (y2-y1)
Run -----> difference in x-coordinates (x2 - x1)
3) Plugin the values in the below mentioned formula.
1.If slope = 0, then the line is parallel to x-axis.
2. If slope is undefined, then the line is parallel to y-axis.
3. If slope is +ve, then the line slant upwards and if slope = -ve, then the line slant downwards.