Answer:
1. 1/2
2. 1/2
3. 1/4
Explanation:
Let the allele for freckles be A or a while that of dimples be B or b.
A person without freckles but heterozygous for dimples = aaBb
A person who has freckles (whose mother has no freckles) but no dimples = Aabb
aaBb x Aabb
Offspring
4 AaBb - freckled and dimpled
4 Aabb - freckled and non dimpled
4 aaBb - non freckled and dimpled
4 aabb - non freckled and non dimpled
1. <em>Probability that the parents will have a dimpled child</em> = 8/16 or 1/2
2. <em>Probability that they will have a child with freckles</em> = 8/16 or 1/2
3. <em>Probability that they will have a child with freckles and dimples</em> = 4/16 or 1/4
<u>See the attached image for the Punnet's square analysis of the cross</u>
Answer: the glucose is a weird circle thing and a french fry is a food.
Explanation: not really understanding the question here...
Answer:
I believe the answer is d
Here, given-
homozygous alleles 'a' have a frequency of 0.3.
Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.
The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.
Calculation-
Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-
Thus, the individuals homozygous for the allele can be calculated by 
Learn more about the Hardy-Weinberg equilibrium here-
brainly.com/question/16823644
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b) some bacteria reduce nitrate ion
