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Lena [83]
4 years ago
6

100 POINTS ANSWER FAST

Chemistry
2 answers:
Alla [95]4 years ago
5 0
100 POINTS ANSWER FASTKatie traveled southwest a distance of 4000m on a bicycle in 5400s. What is her velocity? (velocity = change in distance / change in time)

A.074m/s 
alex41 [277]4 years ago
5 0

nnnnnnnnnnnnnnnnnnnnnnnnnnnooooooooooooooooooooooooooooooooo

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4Cr(s)+3O2 (g )= Cr2O3 (s)<br> Find the theoretical yield in moles and grams
Assoli18 [71]
The balanced reaction is:

<span>4Cr(s)+3O2 (g )= Cr2O3 (s)

Since we are not given the amount of any of the reactants, we assume we have one gram of chromium. Calculations are as follows:

1 g Cr ( 1 mol Cr / 52 g Cr ) ( 1 mol Cr2O3 / 4 mol Cr ) = <span>0.005 mol Cr2O3

</span></span>0.005 mol Cr2O3 (151.99 g Cr2O3 / 1 mol Cr2O3 ) = 0.7307 g <span>Cr2O3
</span>
Therefore, the theoretical yield for 1 gram of Cr is 0.005 mol Cr2O3 or 0.7307 g Cr2O3.
7 0
3 years ago
2. If 4c-3= -31, what is the value of -2c+11
svetoff [14.1K]

Explanation:

see the pic for the answer

5 0
3 years ago
A rectangular tank is filled with water to a depth = h, the tank width and length are w and 1 respectively. Calculate the ratio
AnnZ [28]

Answer:

\frac{\textup{2}}{h}

Explanation:

Given:

Depth = h

Width = w

Length  = 1

Now,

Let ρ be the density of water

Thus,

Pressure force at the bottom will be

= Pressure × Area

= ρgh × (w × 1)

also,

Pressure force at the sides will be = \frac{\textup{1}}{\textup{2}}\times ρgh × (h × w)

Therefore,

The ratio of the pressure force at the bottom to the pressure force on the side of the tank will be

= \frac{\rho gh\times w\times1}{\frac{1}{2}\times\rho gh\times(h\timesw)}

= \frac{\textup{2}}{h}

8 0
3 years ago
What part of an atom bonds with other atoms
mote1985 [20]
Atoms that share electrons in a chemical bond have covalent bonds. An oxygen molecule (O2) is a good example of a molecule with a covalent bond. Ionic bonds occur when electrons are donated from one atom to another.
7 0
4 years ago
Read 2 more answers
How many grams (of mass m) of glucose are in 285 ml of a 5.50% (m/v) glucose solution?
ZanzabumX [31]
The percentage of glucose given is m/v. This means that the given percentage of volume consists of mass.
In this solution, percentage of glucose is 5.5% m/v.
This means that 5.5% of the volume is the mass of glucose.
Given volume is 285 mL. 
Therefore mass of glucose is 5.50% of 285 mL = (5.5*285)/100
mass of glucose = 15.67 g
4 0
3 years ago
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