Answer: 5.85kJ/Kmol.
Explanation:
The balanced equilibrium reaction is

The expression for equilibrium reaction will be,
![K_p=\frac{[p_{D}]\times [p_{C}]}^4{[p_{B}]^2\times [p_{A}]}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%5Bp_%7BD%7D%5D%5Ctimes%20%5Bp_%7BC%7D%5D%7D%5E4%7B%5Bp_%7BB%7D%5D%5E2%5Ctimes%20%5Bp_%7BA%7D%5D%7D)
Now put all the given values in this expression, we get the concentration of methane.


Relation of standard change in Gibbs free energy and equilibrium constant is given by:

where,
R = universal gas constant = 8.314 J/K/mole
T = temperature = 
= equilibrium constant = 10.6



Thus standard change in Gibbs free energy of this reaction is 5.85kJ/Kmol.
The maximum the fourth shell can have is 32.
Answer:
let assume the atom be x so the charge will be x^+
The answer is each indicator has a narrow range. We need many different indicators to span the entire ph spectrum because each indicator has a narrow range.
The rate constant is mathematically given as
K2=2.67sec^{-1}
<h3>What is the Arrhenius equation?</h3>
The rate constant for a particular reaction may be calculated with the use of the Arrhenius equation. This constant can be stated in terms of two distinct temperatures, T1 and T2, as follows:

Therefore
KT1= 0.0110^{-1}
T1= 21+273.15
T1= 294.15K
T2= 200
T2=200+273.15
T2= 473.15K
Ea= 35.5 Kj/Mol
Hence, in j/mol R Ea is
Ea=35.5*1000 j/mol R

K2/0.0110 =e^(5.492)
K2/0.0110 =242.74
K2= 242.74*0.0110
K2=2.67sec^{-1}
In conclusion, rate constant
K2=2.67sec^{-1}
Read more about rate constant
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