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galben [10]
4 years ago
13

What part of an atom bonds with other atoms

Chemistry
2 answers:
mote1985 [20]4 years ago
7 0
Atoms that share electrons in a chemical bond have covalent bonds. An oxygen molecule (O2) is a good example of a molecule with a covalent bond. Ionic bonds occur when electrons are donated from one atom to another.
baherus [9]4 years ago
5 0
Each type of atom forms a characteristic number of covalent bonds with other atoms. An example of that is a hydrogen atom with one electron in its outer shell forms only one bond, its out most orbital becomes filled with two electrons.
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A 15.0 kg chunk of ice falls off the top of an iceberg. If the chunk of ice falls 8.00m to to the surface of the water, what is
yulyashka [42]
When we can get the Kinetic energy from this formula KE= 1/2 M V^2
and we can get the potential energy from this formula PE =  M g H

we can set that the kinetic energy at the bottom of the fall equals the potential energy at the top so,
KE = PE
1/2 MV^2 = M g H
1/2 V^2 = g H
when V is the velocity, g is an acceleration of gravitational force and H is the height of the fall.
∴ v^2 = 2 * 9.8 * 8 = 156.8
∴ v= √156.8 = 12.5 m/s
7 0
3 years ago
Calculate the moles of sucrose in a 15.0-g sample of the substance
dalvyx [7]
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3 0
4 years ago
How many moles of water are produced from 373 mol Al??
stepladder [879]
I cannot come up with a reaction which you can convert directly from Al to H2O.

But you can convert from Al2O3 to H2O by adding HCL solvent.
5 0
3 years ago
Read 2 more answers
Which group contains an element that is liquid at stp?
FrozenT [24]
<span>17 (VIA)... bromine is a liquid at STP
</span>
6 0
3 years ago
what is the theoretical mass of xenon tetrafluoride that should form when 130.g of xenon is reacted with 100.g of F2? what is th
serg [7]

Answer:

The answer to your question is: 70.7 %

Explanation:

Equation

                  Xe   +   2F₂    ⇒    XeF₄

limiting reactant = Xe

Xe is the limiting reactant because the ratio is:

theoretical = 131/ 76 = 1.72 g

experimental ratio = 130/100 = 1.3  the amount of F increased.

                     131.3 g of Xe ------------------ 207 g of XeF₄

                     130 g of Xe  -------------------  x

                         x = (130 x 207) / 131.3

                        x = 205 g of XeF₄

% yield = 145 / 205 x 100

% yield = 70.7

5 0
3 years ago
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