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KIM [24]
2 years ago
13

The equation 3y=5x represents a proportional relationship. what is the constant of proportionality for this relationship

Mathematics
1 answer:
Citrus2011 [14]2 years ago
4 0

The constant of proportionality for this relationship is  \frac{5}{3}

Step-by-step explanation:

Proportional relationship is the relation between two variables that vary directly with each other

  • If x and y are proportion, then y = k x, where k is the constant of proportionality
  • If x and y are proportion, then \frac{y}{x}=k, where k is the constant of proportionality

∵ The equation is 3 y = 5 x

∵ x and y are proportional

- That means y = k x, where k is the constant of proportionality

∴ Put the equation in the form y = k x

- Divide both side by the coefficient of y

∵ The coefficient of y is 3

∴ Divide both sides of the equation by 3

∴ y = \frac{5}{3} x

-  The value \frac{5}{3}  is constant

∴ k =  \frac{5}{3}

∵ k represents the constant of proportionality

∴ The constant of proportionality =  \frac{5}{3}

The constant of proportionality for this relationship is  \frac{5}{3}

Learn more:

You can learn more about the proportional relationship in brainly.com/question/10708697

#LearnwithBrainly

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The arithmetic mean is calculated by adding -3 to the term prior to it. 

            a2 = -21 + -3 = -24               a3 = -24 + -3 = -27
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3 years ago
Find sin (A-B) if sin A = 4/5 with A between 90 and 180 and if cos B = 3/5 with B between 0 and 90
quester [9]

Answer:

sin(A-B) = 24/25

Step-by-step explanation:

The trig identity for the differnce of angles tells you ...

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We are given that sin(A) = 4/5 in quadrant II, so cos(A) = -√(1-(4/5)^2) = -3/5.

And we are given that cos(B) = 3/5 in quadrant I, so sin(B) = 4/5.

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sin(A-B) = (4/5)(3/5) -(4/5)(-3/5) = 12/25 + 12/25 = 24/25

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Hey there!
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Step-by-step explanation:

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