The prime factors of 6 are 2 and 3. So for a number to be divisible by 6,it must also be divisible by 2 and 3.Therefore,we need to check if a number is even and then check if the sum of the digits is divisible by 3
12, 4
take the first number together than the last ones and just find the difference
Answer: The answer would be A. 5
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Answer:
c=0
Step-by-step explanation:
ATQ a.b=|a||b|sin(45)
1+c=sqrt(1+c^2)*sqrt(2)*1/sqrt(2)
1+c=sqrt(1+c^2)
(1+c)^2=(1+c^2)
2c=0, c=0
