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Natalka [10]
3 years ago
7

Four members from a 56​-person committee are to be selected randomly to serve as​ chairperson, vice-chairperson,​ secretary, and

treasurer. The first person selected is the​ chairperson; the​ second, the​ vice-chairperson; the​ third, the​ secretary; and the​ fourth, the treasurer. How many different leadership structures are​ possible? There are nothing possible different leadership structures.
Mathematics
1 answer:
andrew11 [14]3 years ago
6 0

Answer: Total way of choose different leadership structure = 8814960

Step-by-step explanation:

Given - Four members from a 56​-person committee are to be selected randomly to serve as​ chairperson, vice-chairperson,​ secretary, and treasurer.

(1) If we choose first as chairperson we have 56 possibilities to choose

(2)  If we choose second as vice - chairperson we have 55 possibilities to choose

(3)  If we choose third as secretary we have 54 possibilities to choose

(4)  If we choose fourth as secretary we have 53 possibilities to choose

Total way of choose different leadership structure =

  = 56\times55\times54\times53

  = 8814960

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