Answer:

Step-by-step explanation:
Quadratic function is given as 
Let's find a, b and c:
Substituting (0, 6):



Now that we know the value of c, let's derive 2 system of equations we would use to solve for a and b simultaneously as follows.
Substituting (2, 16), and c = 6








=> (Equation 1)
Substituting (3, 33), and c = 6








=> (Equation 2)
Subtract equation 1 from equation 2 to solve simultaneously for a and b.


Replace a with 4 in equation 2.
The quadratic function that represents the given 3 points would be as follows:



Answer:
4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define</u>
a = 3, b = 5, c = 1
b - c
<u>Step 2: Evaluate</u>
- Substitute: 5 - 1
- Subtract: 4
Answer:
2/7
Step-by-step explanation:
there are 2 gray prices out of 7
Best Answer: <span>4/3x-6y, 1/5x-10y
= 4/3(x-2y) , 1/5(x-2y)
LCD = 3 × 5(x – 2y) = 15(x – 2y</span>