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marta [7]
3 years ago
12

A commander wants to arrange his soldiers in such a way that the number of row is equal to the number of columns. If the total n

umber of soldiers is 2800, find how many soldiers would be left out in this arrangement? Also, find the number of rows in the arrangement.
Mathematics
1 answer:
Alla [95]3 years ago
7 0
96 will be left out and there will be 52 rows
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Can someone help me please?
Flura [38]

Answer:

72/100

Step-by-step explanation:

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3 years ago
A baseball player makes a hit 3 out of every 4 at bats. What is the probability that they get two hits in a row
pav-90 [236]
3/4  * 2 = 1.5 % hits
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3 years ago
A rectangular goat pen is 9 meters long and 6 meters wide. What is its perimeter?
andreyandreev [35.5K]

Answer:

30 meters

Step-by-step explanation:

Perimeter is 2L + 2W

So, it would be 2x9+2x6

that is 18+12

= 30 meters

8 0
3 years ago
The attendance at baseball games at a certain stadium is normally distributed, with a mean of 30,000 and a standard deviation of
lakkis [162]

Answer:

a) 0.964

b) 0.500

c) 0.885

d) x \geq 32467.5

e) 0.997      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 30000

Standard Deviation, σ = 1500

We are given that the distribution of attendance at stadium is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(attendance is greater than 27,300)

P(x > 27300)

P( x > 27300) = P( z > \displaystyle\frac{27300 - 30000}{1500}) = P(z > -1.8)

= 1 - P(z \leq -1.8)

Calculation the value from standard normal z table, we have,  

P(x > 27300) = 1 - 0.036 = 0.964 = 96.4\%

b) P(attendance greater than or equal to 30000)

P(x > 30000) = P(z > \displaystyle\frac{30000-30000}{1500}) = P(z \geq 0)\\\\P( z \geq 0) = 1 - P(z \leq 0)

Calculating the value from the standard normal table we have,

1 - 0.500 = 0.500 = 50\%

c) P(attendance between 27000 and 32000)

P(27000 \leq x \leq 32000) = P(\displaystyle\frac{27000 - 30000}{1500} \leq z \leq \displaystyle\frac{32000-30000}{1500}) = P(-2 \leq z \leq 1.33)\\\\= P(z \leq 1.33) - P(z < -2)\\= 0.908 - 0.023 = 0.885 = 88.5\%

P(27000 \leq x \leq 32000) = 88.5\%

e) P(attendance less than 33000)

P(x < 33000)

P( x < 33000) = P( z < \displaystyle\frac{33000 - 30000}{1500}) = P(z < 2)

Calculating the value from the standard normal table we have,

P(x < 33000)  = 0.997 = 99.7%

d) We have to find x such that:

P( X > x) = P( z > \displaystyle\frac{x - 30000}{1500}) = 0.95

Calculating the value from the standard normal table we have,

P(z = 1.645) = 0.95

Thus,

\displaystyle\frac{x - 30000}{1500} \geq 1.645\\\\x \geq 32467.5

The attendance should be greater than or equal to 32467.5 to be in the top 5% of all games.

6 0
4 years ago
7 cups to 9 pints into a fraction simplified
Natali [406]
There are 2 cups in 1 pint. That's a hint.

7 0
3 years ago
Read 2 more answers
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