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2 years ago

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A commander wants to arrange his soldiers in such a way that the number of row is equal to the number of columns. If the total n

umber of soldiers is 2800, find how many soldiers would be left out in this arrangement? Also, find the number of rows in the arrangement.

1 answer:

Alla [95]2 years ago

7 0

96 will be left out and there will be 52 rows

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Which product is positive?

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Option D:

$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$ is positive product.

Solution:

<em>If the negative sign is in even number of times then the product is positive.</em>

<em>If the negative sign is in odd number of times then the product is negative.</em>

To find which product is positive:

Option A:

$$\left(\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option B:

$$\left(-\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(-\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative signs = 3

3 is an odd number.

So, the product is negative.

Option C:

$$\left(\frac{2}{5}\right)\left(\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(-\frac{2}{7}\right)$

Here, number of negative sign = 1

1 is an odd number.

So, the product is negative.

Option D:

$$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$

Here, number of negative sign = 2

2 is an odd number.

So, the product is positive.

Hence option D is the correct answer.

$\left(-\frac{2}{5}\right)\left(-\frac{8}{9}\right)\left(\frac{1}{3}\right)\left(\frac{2}{7}\right)$ is positive product.

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C=1.50r would be the correct answer

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Answer:

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2 years ago

I NEED HELP :_( Which of the following points is in the solution set of y > -x∧2 + 5? (0, 5) (2, 4) (1, 3)

marysya [2.9K]

Answer:

$\huge\boxed{(2;\ 4)}$

Step-by-step explanation:

We have

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$5>-0^2+5\\5>0+5\\5>5\qquad\bold{FALSE}$

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Answer:

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