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3 years ago

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A commander wants to arrange his soldiers in such a way that the number of row is equal to the number of columns. If the total n

umber of soldiers is 2800, find how many soldiers would be left out in this arrangement? Also, find the number of rows in the arrangement.

1 answer:

Alla [95]3 years ago

7 0

96 will be left out and there will be 52 rows

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Translate each sentence into an equation.

mihalych1998 [28]

Answer:

1. 1/2x = 4

2. x - 6 = 9

3. 2x = 5x + 12

4. 2x + 5 = x - 5

5. 2x + 11 = x - 5

Hope this helps you!

3 0

3 years ago

It is known that 10% of adults can pass a fitness test. What notation would be used to describe a count of the number of adults

Andrej [43]

Answer: B. x ~ B(50, .1)

In other words, it's the second answer choice

===========================================================

Explanation:

We have n = 50 people in the sample and p = 0.10 is the decimal form of 10%, to represent the probability of success. In this case, we define "success" as "the person passes the fitness test".

The random variable x is the count of how many people pass. So we could have x = 0, x = 1, x = 2, ..., x = 49, x = 50. Basically any whole number from 0 to 50 inclusive. Furthermore, x is approximately modeled by the binomial distribution which we denote as B(n, p) = B(50, 0.1)

So X ~ B(50, 0.1)

3 0

3 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago

How many solutions does the following equation have? (5 points)<br> 4x+ 12 = 0

zhenek [66]

One solution ! Which is x=-3

8 0

3 years ago

Simplify (-a2b3)2(c2)0

Jobisdone [24]

The correct answer is
<span>a4b<span>6 I think also your question is missed up next time fix it</span></span>

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3 years ago

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