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2 years ago

Can someone help with this question please?

Mathematics

1 answer:

lakkis [162]2 years ago

8 0

I that the answer is A

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What all numbers whose absolute value is 6

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Answer:

6, -6

Explanation:

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A garden is in the shape of a square. The length of one side of the garden is

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45,796 feet squared, assuming the length of one side is 214 feet.

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Sally can paint a room in 4hours while it takes Steve 3 hours to paint the same room. How long would it take them to paint the r

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Slope of (0,45) (6,33) (15,15)

Vladimir [108]

Answer:

The slope is -2

Step-by-step explanation:

Given

$(x_1,y_1) = (0,45)$

$(x_2,y_2) = (6,33)$

$(x_2,y_3) = (15,15)$

Required

The slope (m)

Slope is calculated as:

$m = \frac{y_2 -y_1}{x_2 - x_1}$

So, we have:

$m = \frac{33 -45}{6 - 0}$

$m = \frac{-12}{6}$

$m =-2$

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2 years ago

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

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2 years ago