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3 years ago

The volume of a cube is 27n^27 cubic units. What is the length of one side of the cube?

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

The volume of a cube (V) is given in terms of its side length (s) as

... V = s³

You have

... 27n²⁷ = s³

You may recognize that 27 = 3³, so this can be written as

$3^3\cdot n^{3\cdot 9} = \left(3n^{9}\right)^{3}=s^{3}\\\\3n^{9}=s\qquad\mbox{taking cube roots}$

This result matches your second selection

... 3n⁹ units

lawyer [7]3 years ago

4 0

B) 3n^9 units

I just took the quiz on edge

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Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

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So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

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Answer:

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Step-by-step explanation:

Expand the following:

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4 x^2 x - 3 x^2

x^2×4 x = x^(2 + 1)×4:

4 x^(2 + 1) - 3 x^2

2 + 1 = 3:

Answer: 4 x^3 - 3 x^2

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The image of the given scenario is attached below.

A right angled triangle is formed, with one angle equal to 27 degrees. The perpendicular side is 155 and we are to find the length of guy wire which makes the hypotenuse of the right angled triangle.

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