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3 years ago

Please help me. Is that right?

Mathematics

2 answers:

Alex17521 [72]3 years ago

6 0

Answer:

Angle 5

Step-by-step explanation:

zepelin [54]3 years ago

4 0

Answer:

Yes

Step-by-step explanation:

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Orange juice is sold in four different sizes the 8 1/2 ounce bottle costs $0.99 the 18 2/2 oz. bottle costs $1.49 the 48 1/4 oz.

Valentin [98]

Answer:

Part 1) The units rates are

A) $0.1165\frac{\$}{oz}$

B) $0.1656\frac{\$}{oz}$

C) $0.0516\frac{\$}{oz}$

D) $0.0579\frac{\$}{oz}$

Part 2) The best buy is the size 48 1/4 oz

Step-by-step explanation:

we know that

To find out the unit rate divide the total cost by the total volume

Part 1) Calculate the unit rate for each size

case A) we have

8 1/2 ounce bottle costs $0.99

Convert mixed number to an improper fraction

$8\frac{1}{2} =\frac{8*2+1}{2}=\frac{17}{2}\ oz$

Find the unit rate

$\frac{0.99}{(17/2)}= 0.1165\frac{\$}{oz}$

case B) we have

18 2/2 oz. bottle costs $1.49

Convert mixed number

$18\frac{2}{2} =18+1=19\ oz$

Find the unit rate

$\frac{1.49}{19}= 0.1656\frac{\$}{oz}$

case C) we have

48 1/4 oz. carton costs $2.49

Convert mixed number to an improper fraction

$48\frac{1}{4} =\frac{48*4+1}{4}=\frac{193}{4}\ oz$

Find the unit rate

$\frac{2.49}{(193/4)}= 0.0516\frac{\$}{oz}$

case D) we have

64 3/4 oz. carton costs $3.75

Convert mixed number to an improper fraction

$64\frac{3}{4} =\frac{64*4+3}{4}=\frac{259}{4}\ oz$

Find the unit rate

$\frac{3.75}{(259/4)}= 0.0579\frac{\$}{oz}$

Part 2) which size is the best buy

we know that

The best buy is the one with the smallest unit rate

$0.0516\frac{\$}{oz}$

The best buy is the size 48 1/4 oz

3 0

3 years ago

In London today, four times the high temperature was more than twice the high temperature plus

4vir4ik [10]

Answer:

Let's define the high temperature as T.

We know that:

"four times T, was more than 2*T plus 66°C"

(i assume that the temperature is in °C)

We can write this inequality as:

4*T > 2*T + 66°C

Now we just need to solve this for T.

subtracting 2*T in both sides, we get:

4*T - 2*T > 2*T + 66°C - 2*T

2*T > 66°C

Now we can divide both sides by 2:

2*T/2 > 66°C/2

T > 33°C

So T was larger than 33°C

Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.

Then the range of possible temperatures is:

(33°C, ...)

Where we do not have an upper limit, so we could write this as:

(33°C, ∞°C)

(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)

4 0

3 years ago

on monday janelle earned $16 for 2 hours of baby sitting. getting payed at the same rate if she wanted to make 40$ babysitting o

zhuklara [117]

Answer:

40/16

2 x 40/16

80/16

= 5

she would have to work 5 hours

6 0

3 years ago

Marianne, Arlene, Tyler, and I worked together to complete a group project. Marianne completed 1/5 of the project. Arlene comple

Nookie1986 [14]

Marianne completed 2/10 and Arlene 3/10 so that’s 5/10 which means you and Tyler did 5/10 if you divide that by 2 it’s 5/20 I think but I don’t really understand as the possible answers aren’t fractions? Hopefully that’s right haha

3 0

4 years ago

A ball is projected horizontally from the top of a building. One second later, another ball is projected horizontally from the s

ehidna [41]

Answer:

t = 0 at the start of the projection

Step-by-step explanation:

To solve this we need to find the distance between the 2 positions at any given time, then solve for the least distance

Let t be the time of the 2nd ball, so t + 1 is the time of the first ball

Let g be the gravitational acceleration, v be the horizontal velocity

the y coordinates of the first and 2nd balls

$y_1 = -g(t+1)^2/2$

$y_2 = -gt^2/2$

The x coordinates of the 1st and 2nd balls:

$x_1 = v(t+1)$

$x_2 = vt$

The distance between the 2 balls is

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

$d = \sqrt{(v(t + 1) - vt)^2 + (-g(t+1)^2/2 - (-gt^2/2))^2}$

$d = \sqrt{(vt + v - vt)^2 + g/4(t^2 - (t^2 + 2t + 1))^2}$

$d = \sqrt{v^2 + (g/4)(-2t-1)^2}$

$d = \sqrt{v^2 + (g/4)(2t+1)^2}$

As both v and g are constant and cannot be changed, d is minimum when (2t + 1) is minimum, which happens only when t is minimum = 0

7 0

3 years ago