Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
The answer is (5,4). X being the run (5), and Y being the rise (4).
9514 1404 393
Answer:
C 3x +1 = y
Step-by-step explanation:
x-values increase by 1 from row to row.
y-values increase by 3 from row to row.
The slope of the linear function is the ratio of the y-increase to the x-increase:
m = ∆y/∆x = 3/1 = 3
The only offered choice with an x-coefficient of 3 is ...
C 3x +1 = y
__
If you check this against the table entries, you find it fits.
3(1) +1 = 4
3(2) +1 = 7
and so on.
Answer:6
Step-by-step explanation:
Answer:
Step-by-step explanation:
perp. -4/3
y + 2 = -4/3(x - 3)
y + 2 = -4/3x + 4
y = -4/3x + 2