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2 years ago

¿Cuál es la razón para que los planetas y los electrones no abandonen sus órbitas saliendo expulsados sin regreso?

Chemistry

1 answer:

bazaltina [42]2 years ago

4 0

Answer:

I wish I could speak Spanish

Explanation:

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2 H2O2(aq) ----> 2 H2O(l) + O2(g) in the presence of I-(aq) is proposed to be: Step 1 (slow): H2O2 + I- -----> H2O + OI- S

andrezito [222]

Answer:

Molecularity of the rate determining step = 2

Explanation:

Step 1 (slow): H₂O₂ + I⁻ -----> H₂O + OI⁻

Step 2 (fast): H₂O₂ + OI⁻ -----> H₂O + O₂ + I⁻

The rate determining step in a reaction mechanism is also considered as slowest step.

Slowest step is also considered its highest activation energy in energy profile diagram.

In this case intermediate (IO⁻) is formed.

Step 1 considered as a slowest step.

So, Rate = K [H₂O₂][I⁻]

Molecularity = 2

6 0

3 years ago

The transfer of energy that occurs when a force is applied over a distance is

nika2105 [10]

The transfer of energy that occurs when a force is applied over a distance is WORK.

Hope this helps!

3 0

3 years ago

1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?

RSB [31]

Answer : The number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

$PV=nRT$

where,

P = Pressure of $N_2$ gas = $1.00\times 10^{-6}mmHg=1.32\times 10^{-9}atm$ (1 atm = 760 mmHg)

V = Volume of $N_2$ gas = 985 mL = 0.982 L (1 L = 1000 mL)

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $0.0^oC=273+0.0=273K$

Now put all the given values in above equation, we get:

$(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K$

$n=5.78\times 10^{-11}mol$

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains $6.022\times 10^{23}$ number of molecules.

As, 1 mole of $N_2$ gas contains $6.022\times 10^{23}$ number of molecules

So, $5.78\times 10^{-11}$ mole of $N_2$ gas contains $(5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13}$ number of molecules

Therefore, the number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

8 0

3 years ago

Ayyyy Country <br> #12 ⚾<br> how u doin?

mr_godi [17]

Explanation:

you look like a mohammed. im good, hbu?

6 0

3 years ago

Read 2 more answers

Calculate the molarity of a solution that contains 4.7 moles in 5.2 liters.

AleksAgata [21]

Answer:

0.9M

Explanation:

molarity = mols/L

M=4.7mol/5.2L

= 0.9M

4 0

3 years ago