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Zinaida [17]
3 years ago
12

Two compounds with general formulas A2X and AX3 have Ksp=1.5×10−5M. Part A Which of the compounds has the higher molar solubilit

y? Which of the compounds has the higher molar solubility? A2X AX3
Chemistry
2 answers:
DiKsa [7]3 years ago
8 0

Hey there!:

To get to the molar solubility from the Ksp, you have to think about the how Ksp is calculated, and what it means.  

For a compound that forms 2 ions, Ksp = X^2 where X is the molar solubility. For a compound that forms 3 ions, Ksp = 4X^3, where again, X is the molar solubility.  

If you calculate the molar solubilities of each of your compounds, you will see that  A2X  has the higher molar solubilty

Hope this helps!

vovikov84 [41]3 years ago
5 0

Answer:

A₃X

Explanation:

In order to find the molar solubility (S) of a compound, we will use an ICE Chart.

A₂X

Let's consider the solution of A₂X.

     A₂X(s) ⇄ 2 A⁺(aq) + X²⁻(aq)

I                         0           0

C                     +2S        +S

E                       2S          S

The solubility product (Kps) is:

Kps = 1.5 × 10⁻⁵ = [A⁺]².[X²⁻] = (2S)².S = 4S³

S = 0.016 M

A₃X

Let's consider the solution of A₃X.

     A₃X ⇄ 3 A⁺(aq) + X³⁻(aq)

I                    0             0

C                 +3S         +S

E                   3S           S

The solubility product (Kps) is:

Kps = 1.5 × 10⁻⁵ = [A⁺]³.[X³⁻] = (3S)³.S = 27 S⁴

S = 0.027 M

A₃X has a higher molar solubility than A₂X.

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Ede4ka [16]

Answer:

32.6 %

Explanation:

Given data

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Step 1: Calculate the mass of the solution

The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.

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Answer:

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Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

.The empirical formula for a compound is CH2. If n is a whole number, which shows a correct relationship between the molecular formula and the empirical formula? a)<br /><br /> empirical formula mass / molecular mass = n<br /><br /> B) molecular mass = element mass / empirical formula mass ´ 100<br /><br /> c) subscript of H in empirical formula = 2  subscript of H in molecular formula<br /><br /> D) subscript of C in molecular formula = n  subscript of C in empirical formula<br /><br />

An empirical formula can be regarded as "shorten form" of a molecular formula. Instance of this is

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Therefore, subscript of C in molecular formula = n x subscript of C in empirical formula

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