Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions
We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M
The final concentration is 1.5 M
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Answer:
50 mol CH₄
Explanation:
The question is incomplete so I looked it up online.
<em>How many moles CH₄, are needed to produce 50 moles of CO₂?</em>
Step 1: Write the balanced equation for the complete combustion of methane
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of CH₄ to CO₂ is 1:1.
Step 3: Calculate the number of moles of CH₄ needed to produce 50 moles of CO₂
We will use the previously established molar ratio.
50 mol CO₂ × 1 mol CH₄/1 mol CO₂ = 50 mol CH₄
Answer:
15.95 g
Explanation:
Calculation of the moles of sulfur as:-
Mass = 3.5 g
Molar mass of sulfur = 32.065 g/mol
The formula for the calculation of moles is shown below:
Thus,
From the reaction,

1 mole of sulfur on reaction forms 1 mole of sulfur hexafluoride
0.1092 mole of sulfur on reaction forms 0.1092 mole of sulfur hexafluoride
Molar mass of sulfur hexafluoride = 146.06 g/mol
Mass= Moles*Molar mass = 0.1092*146.06 g = 15.95 g
<u>15.95 g is the maximum amount of
that can be produced from the reaction of 3.5 g of sulfur with of fluorine.</u>
8E24/6.022E23= 13.28 moles, where the denominator is Avagadro's number