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Zinaida [17]
3 years ago
12

Two compounds with general formulas A2X and AX3 have Ksp=1.5×10−5M. Part A Which of the compounds has the higher molar solubilit

y? Which of the compounds has the higher molar solubility? A2X AX3
Chemistry
2 answers:
DiKsa [7]3 years ago
8 0

Hey there!:

To get to the molar solubility from the Ksp, you have to think about the how Ksp is calculated, and what it means.  

For a compound that forms 2 ions, Ksp = X^2 where X is the molar solubility. For a compound that forms 3 ions, Ksp = 4X^3, where again, X is the molar solubility.  

If you calculate the molar solubilities of each of your compounds, you will see that  A2X  has the higher molar solubilty

Hope this helps!

vovikov84 [41]3 years ago
5 0

Answer:

A₃X

Explanation:

In order to find the molar solubility (S) of a compound, we will use an ICE Chart.

A₂X

Let's consider the solution of A₂X.

     A₂X(s) ⇄ 2 A⁺(aq) + X²⁻(aq)

I                         0           0

C                     +2S        +S

E                       2S          S

The solubility product (Kps) is:

Kps = 1.5 × 10⁻⁵ = [A⁺]².[X²⁻] = (2S)².S = 4S³

S = 0.016 M

A₃X

Let's consider the solution of A₃X.

     A₃X ⇄ 3 A⁺(aq) + X³⁻(aq)

I                    0             0

C                 +3S         +S

E                   3S           S

The solubility product (Kps) is:

Kps = 1.5 × 10⁻⁵ = [A⁺]³.[X³⁻] = (3S)³.S = 27 S⁴

S = 0.027 M

A₃X has a higher molar solubility than A₂X.

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joja [24]
Here, we apply a mass balance:
Moles of chloride ions in final solution = sum of moles of chloride ions in added solutions

We must also not that each mole of sodium chloride will release one mole of chloride ions, while each mole of magnesium chloride will release two moles of chloride ions.
Moles = concentration * volume
Moles in final solution = moles in NaCl solution + moles in MgCl₂ solution
C * (150 + 250) = 1.5 * 150 + 2 * 0.75 * 250
C = 1.5 M

The final concentration is 1.5 M
4 0
3 years ago
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Ahat [919]

please try to keep questions acedemic related

it does no good for questions like this to be on here when others need help, try to keep your questions..

  - Partained to the particular subject
  - presented in the correct language and maner
  - understandable and with all the information needed

no hard feelings, though this question and answer will be deleted by moderators soon so just keep all that in mind ^^

8 0
2 years ago
4 How many moles CH, are needed to produce 50 moles of CO2?
exis [7]

Answer:

50 mol CH₄

Explanation:

The question is incomplete so I looked it up online.

<em>How many moles CH₄, are needed to produce 50 moles of CO₂?</em>

Step 1: Write the balanced equation for the complete combustion of methane

CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O

Step 2: Establish the appropriate molar ratio

According to the balanced equation, the molar ratio of CH₄ to CO₂ is 1:1.

Step 3: Calculate the number of moles of CH₄ needed to produce 50 moles of CO₂

We will use the previously established molar ratio.

50 mol CO₂ × 1 mol CH₄/1 mol CO₂ = 50 mol CH₄

3 0
3 years ago
Sulfur and fluorine react in a combination reaction to produce sulfur hexafluoride: S (s) 3F 2(g) SF 6 (g) The maximum amount of
earnstyle [38]

Answer:

15.95 g

Explanation:

Calculation of the moles of sulfur as:-

Mass = 3.5 g

Molar mass of sulfur = 32.065 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

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Moles= 0.1092\ mol

From the reaction,

S+3F_2\rightarrow SF_6

1 mole of sulfur on reaction forms 1 mole of sulfur hexafluoride

0.1092 mole of sulfur on reaction forms 0.1092 mole of sulfur hexafluoride

Molar mass of sulfur hexafluoride = 146.06 g/mol

Mass= Moles*Molar mass = 0.1092*146.06 g = 15.95 g

<u>15.95 g is the maximum amount of SF_6 that can be produced from the reaction of 3.5 g of sulfur with of fluorine.</u>

7 0
4 years ago
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kirza4 [7]
8E24/6.022E23= 13.28 moles, where the denominator is Avagadro's number
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