Answer:
Explanation:
From the question we are told that
Frequency of light 
Generally the equation for wave is mathematically given as
Where
Generally the equation for a fundamental Frequency is mathematically given as
Therefore the length of the smallest standing wave
Answer:
Explanation:
Let the charge on proton be q .
energy gain by proton in a field having potential difference of V₀
= V₀ q
Due to gain of energy , its kinetic energy becomes 1/2 m v₀²
where m is mass and v₀ is velocity of proton
V₀ q = 1/2 m v₀²
In the second case , gain of energy in electrical field
= 2 V₀q , if v be the velocity gained in the second case
2 V₀q = 1/2 m v²
1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²
mv² = 2 m v₀²
v = √2 v₀
Answer:
5N
Explanation:
Given parameters:
Original length = 22cm
Spring constant, K = 50N/m
New length = 32cm
Unknown
Force applied = ?
Solution:
The force applied on a spring can be derived using the expression below;
Force = KE
k is the spring constant
E is the extension
extension = new length - original length
extension = 32cm - 22cm = 10cm
convert the extension from cm to m;
100cm = 1m;
10cm will give 0.1m
So;
Force = 50N/m x 0.1m = 5N
Answer:
The new intensity = 3.38 × 10⁻⁵ W/m²
Explanation:
Intensity of sound wave:
The intensity of sound is the rate of flow of flow of energy, per unit area, perpendicular to the direction of the sound wave.
Intensity (I) ∝ A²
where I = intensity, A = Amplitude.
∴ I₁/I₂ = A₁²/A²₂............................... equation 1
From the question, the amplitude increase by 30% of the initial
∴ A₂ = A₁ + 0.3A₁ = 1.3A₁, I₁ = 2.00×10⁻⁵ W/m²
∴ (2.00×10⁻⁵)/I₂ = A₁²/(1.3A₁)²
(2.00×10⁻⁵)/I₂ = 1/1.3²
making I₂ the subject of the equation
I₂ = (2.00 × 10⁻⁵)×1.3² = 3.38 × 10⁻⁵ W/m₂
The new intensity = 3.38 × 10⁻⁵ W/m²
Answer:
3420.39 N
Explanation:
Applying,
Fd = 1/2(mv²-mu²)................. Equation 1
Where F = force on the bumber, d = distance, m = mass of the car, v = final velocity, u = initial velocity.
make F the subject of the equation
F = (mv²-mu²)/2d............... Equation 2
From the question,
Given: m = 890 kg, v = 0 m/s (to rest), u = 1.4 m/s, d = 0.255 m
Substitute these values into equation 2
F = [(890×0²)-(890×1.4²)]/(2×0.255)
F = -1744.4/0.51
F = -3420.39 N
The negative sign denotes that the force in opposite direction to the motion of the car.
