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galben [10]
3 years ago
12

A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

a potential difference of 2V0, what speed would it gain
Physics
1 answer:
Neporo4naja [7]3 years ago
6 0

Answer:

Explanation:

Let the charge on proton be q .

energy gain by proton in a field having potential difference of V₀

= V₀ q

Due to gain of energy , its kinetic energy becomes 1/2 m v₀²

where m is mass and v₀ is velocity of proton

V₀ q = 1/2 m v₀²

In the second case , gain of energy in electrical field

= 2 V₀q , if v be the velocity gained in the second case

2 V₀q = 1/2 m v²

1/2 m v² = 2 V₀q = 2 x 1/2 m v₀²

mv² = 2  m v₀²

v = √2 v₀

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Answer:

(a) 380.96 pC

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Explanation:

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3 years ago
A box is being moved with a velocity (v) by a force P (parallel to v) along a level horizontal floor. The normal force is (Fn),
labwork [276]

Answer:

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Explanation:

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Since, force P is parallel to the motion of the box. Therefore, θ = 0°

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Since, normal force and weight are perpendicular to the motion of the box. Therefore, θ = 90°

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Since, kinetic frictional force acts in the opposite direction of motion of the box. Therefore, θ = 180°

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