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Tema [17]
3 years ago
6

Find the length of the smallest standing wave that can be formed with light having frequency 600 THz

Physics
1 answer:
Reika [66]3 years ago
4 0

Answer:

L=2.5*10^-^7m

Explanation:

From the question we are told that

Frequency of light  f= 600 THz

Generally the equation for wave is mathematically given as

\lambda=\frac{c}{\gamma}

Where

1THz=10^1^2

\lambda=\frac{3*10^8}{600*10^1^2}

\lambda=0.5*10^-^6m

Generally the equation for a fundamental Frequency  is mathematically given as

L=\frac{\lambda}{2}

L=\frac{0.5*10^-^6}{2}

Therefore the length of the smallest standing wave

L=2.5*10^-^7m

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An engineer is investigating energy loss through windows. The windowpane of interest is 0.650 cm thick, has dimensions of 1.19 m
krok68 [10]

Answer:

7908.92307 W

683330953.248 J

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 1.19\times 2.25\ m^2

l = Thickness = 0.65 cm

T_2 = 24°C

T_1 = 0°C

Rate of heat transfer is given by

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 1.19\times 2.25(24-0)}{0.65\times 10^{-2}}\\\Rightarrow Q=7908.92307\ W

The rate of heat transfer is 7908.92307 W

Amount of energy is given by

E=Qt\\\Rightarrow E=7908.92307\times 24\times 3600\\\Rightarrow E=683330953.248\ J

The energy transferred through the window in one day is 683330953.248 J

8 0
3 years ago
9. When considering a magnet's force of attraction over a known distance, you would expect the strength of attraction 4 inches a
slavikrds [6]

Answer: B. 16 times

Explanation:

The mathematic expression for a magnetic force F_{M} between two magnets is:

F_{M}=K_{M}\frac{m_{1}m_{2}}{r^{2}}   (1)

Where:

K_{M} is a constant

{m_{1} and {m_{2} are the magnetic charges, which depends on the size of each magnet

r is the distance beteween both magnets

As we can see, this force in inversely proportional to the square of the distance. This means that if we increase the distance, the magnetic force will decrease.

Now, if we increase this value by 4 inches from 1 inch:

F_{M}=K_{M}\frac{m_{1}m_{2}}{{(4)}^{2}}   (2)

F_{M}=K_{M}\frac{m_{1}m_{2}}{16}   (3)

This means the strength of attraction will be 16 times weaker.

3 0
4 years ago
a man weighs 600 n while on the surface of earth. if he is transported to the planet mythos which has the same mass as earth but
faltersainse [42]

Answer:

24N

Explanation:

Calculation for what his weight would be

Let his WEIGHT on the surface of earth be 600 and Let the RADIUS be 25 which is (5^²) because we were told that the radius is FIVE TIMES larger than earths

Now let calculate his weight using this formula

Weight=Weight on Earth/Radius

Let plug in the formula

Weight=600N/5^²

Weight=600N/25

Weight=24N

Therefore his weight would be 24N

3 0
3 years ago
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