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svetoff [14.1K]
3 years ago
12

if 4 people want tk use a canoe that can only hold up to 800 pounds and they have 60 pounds of gear, what must the average weigh

t of each person math problem
Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

185 pounds

800 - 60 = 740

740 ÷ 4 = 185

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Which answer describes the calculations that could be used to solve this problem?
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nikitadnepr [17]

Answer:

The value of x is \frac{-2}{5}.

Step-by-step explanation:

Given expression is:

\frac{2}{3}(x-2)=4x

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3*\frac{2}{3}(x-2)=4x*3

2(x-2) = 12x

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Now we will be subtracting 2x from both sides of the equation

2x-2x-4=12x-2x

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\frac{10x}{10}=\frac{-4}{10}\\\\x=\frac{-2}{5}

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The value of x is \frac{-2}{5}.

8 0
2 years ago
Stephon has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.
alekssr [168]

Answer:  The expressions for the length and width of the new patio are

\ell=x+4,~~w=x-4.

And the area of the new patio is 384 sq. feet.

Step-by-step explanation:  Given that Stephen has a square brick patio. He wants to reduce the width by 4 feet and increase the length by 4 feet.

The length of one side of the square patio is represented by x.

We are to write the expressions for the length and width of the new patio and then to find the area of the new patio if the original patio measures 20 feet by 20 feet.

Since Stephen wants to reduce width of the patio by 4 feet, so the width of the new patio will be

w=(x-4)~\textup{feet}.

The length of the patio is increased by 4 feet, so the length of the new patio will be

\ell=(x+4)~\textup{feet}.

Now, if the original patio measures 20 feet by 20 feet, then we must have

w=x-4=20-4=16~\textup{feet}

and

\ell=x+4=20+4=24~\textup{feet}.

Therefore, the area of the new patio is given by

A_n=\ell \times w=24\times16=384~\textup{sq. feet}.

Thus, the expressions for the length and width of the new patio are

\ell=x+4,~~w=x-4.

And the area of the new patio is 384 sq. feet.

4 0
3 years ago
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