Thanks for the help!

Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

BaLLatris [955]

Answer:

To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.

Step-by-step explanation:

hope its right

3 0

2 years ago

The square of Mark's age 3 years ago is 6 times the age he will be in 9 years. What is his age now?

Lubov Fominskaja [6]

Answer:

Age= 15

Step-by-step explanation:

Let a be for age at the moment

(a-3)^2 =6(a+9)

a^2-6a+9=6a+54

a^2-12a-45

(a-15)(a+3)

a=15 or a=-3

Age cannot be negative (-)

Therefore

Age =15

3 0

3 years ago

Read 2 more answers

Use Laplace transform methods to solve the differential equation: The initial conditions are f(0) = 0 and <img src="https://tex.

Llana [10]

Answer:

Step-by-step explanation:

$\frac{d^2 y}{dt^2} +12\frac{dy}{dt} +32y = 10e^{-2t}$ where f(x) is replaced by y

Take Laplace on both sides

$s^2 Y -s(0)-0 +12s Y-0+32Y = \frac{10}{s+2} \\Y(s^2+12s+32) = \frac{10}{s+2}\\Y = \frac{10}{(s+2)(s+4)(s+8)}$

We can resolve into partial fraction to get Y = L(y)

Let this equals

$\frac{A}{s+2} +\frac{B}{s+4} +\frac{C}{s+8} \\10 = A(s+4)(s+8) + B(s+2)(s+8) +Cs+4)(s+2) \\$

Solving we get

s=-9

24C = 10 or C =5/12

s=-2: A=10/12=5/6

s=-4: B = -5/4

Taking inverse Laplace

$y(t) = \frac{-5e^{-4t} }{4} + \frac{5e^{-8t} }{12} +\frac{-5e^{-2t} }{6}$

6 0

2 years ago

At an ocean depth of 8 meters, a buoy bobs up and then down 5 meters from the ocean's depth. Sixteen seconds pass from the time

lisov135 [29]

Answer:

See attached for a graph

Step-by-step explanation:

We're going to plot sea level as y=0 and a depth of 8 meters as y=-8.

The problem statement tells you the initial point (x=0) is at normal ocean depth (y=-8), so the first point you put into your sine tool is ...

(x, y) = (0, -8)

The buoy takes 16 seconds to go from a high point to a low point, so the time to the first high point is half that, or x=8 seconds. That high point is 5 meters above its average depth, so is at y=-3.

The second point you will put into your sine tool is ...

(x, y) = (8, -3)

7 0

2 years ago

Please help me solve this I forgot how to

RideAnS [48]

2.5

hope it helps//...,d/cmn/lsjdhc;ljwknefv

4 0

3 years ago