Answer:
33º and 147º
Step-by-step explanation:
x + (x + 114) = 180
2x + 114 = 180
2x = 66
x = 33º
x + 114 = 147º
1. Find the derivative of <span>P(x)=3x^3+2x^2-6x. It's P'(x)=9x^2 + 4x - 6.
2. Set this result equal to zero and solve for the critical values:
</span> 9x^2 + 4x - 6 = 0 Using the quadratic formula, I got
x = [-4 plus or minus sqrt(232)] / 18. Reducing this,
x = [-4 plus or minus 2 sqrt(58)]; thus, there are two real, unequal roots and two real, unequal critical values.
3. One at a time, examine the two critical values: determine whether the derivative changes from neg to pos or from pos to neg at each of these values. Example: If the derivative is pos to the left of the first c. v. and neg to the right, we've got a local max.
4. Since there are only 2 critical values, you can have no more than 1 local max (corresponding to a change in the sign of the derivative from pos to neg) and one local min. (from neg to pos).
Message me if this explanation is not sufficient to help you understand this problem thoroughly.
Answers:
-3.5 < 5
|-3.5| < |5|
============================================
Explanation:
Any negative number is <u>always</u> smaller than any positive number. So that's why -3.5 is smaller than 5 and where -3.5 < 5 comes from. It might help to set up a vertical number line. Stuff on top is larger than stuff down below.
---------
The vertical bars represent absolute value. The result of |-3.5| is 3.5 because this is the distance from -3.5 to 0 on the number line. Likewise, |5| = 5.
So that's how we get to |-3.5| < |5| which is effectively saying -3.5 is closer to zero than 5 is to zero.
Answer:
C) Because it is 5 units to the left of 3 on a horizontal number line
Step-by-step explanation:
You have to go 5 steps back to the left of 3 to get to -2.
See attached drawing for visual assistance on this problem:
That is right because you are doing times for you can get your answer you can do adding so it is 192.The volume it would be 22 because you are adding 4+4+6+8=22 so that will be the volume hopes this helps. :)