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Talja [164]
3 years ago
8

How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?

Chemistry
1 answer:
Darya [45]3 years ago
5 0

Answer:

Option C. 0.34 moles

Explanation:

Data obtained from the question include:

Molarity = 0.15M

Volume = 2.25L

Mole =

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.15 x 2.25

Mole = 0.34mole

The number of mole of AlCl3 present in the solution is 0.34mole.

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I believe the answer is a because 2 times 12 is 24. Hope this helped
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3 years ago
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What is the molar concentration of a solution prepared by dissolving 8.63 g of Ba(NO3)2 (molar mass = 261.35 g/mol) to a total v
PilotLPTM [1.2K]

Answer:

我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

Explanation:

我實際上不知道我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈我實際上不知道答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈答案,我只是為了點數而這樣做,哈哈,祝你好運哈哈

7 0
3 years ago
2) what is the mass of 6.02 x 1023 atoms of arsenic?
zzz [600]
Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>

Solving:

1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule

6,02*10²³X = 75
x = \frac{75}{6,02*10^{23}}
\boxed{x \approx 1,24*10^{24}grams}
6 0
3 years ago
What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?
asambeis [7]
KOH+ HNO3--> KNO3+ H2O<span>
From this balanced equation, we know that 1 mol HNO3= 1 mol KOH (keep in mind this because it will be used later).

We also know that 0.100 M KOH aqueous solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the definition of molarity).

First, we should find the mole of KOH:
100.0 mL KOH soln* (1 L KOH soln/ 1,000 mL KOH soln)* (0.100 mol KOH/ 1L KOH soln)= 1.00*10^(-2) mol KOH.

Now, let's find the volume of HNO3 soln:
1.00*10^(-2) mol KOH* (1 mol HNO3/ 1 mol KOH)* (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.

The final answer is </span>(2) 20.0 mL.<span>

Also, this problem can also be done by using dimensional analysis. 

Hope this would help~ </span>
6 0
3 years ago
An iron pipe has a density of 7.86 g/mL and a volume of 324.4 mL. What is the mass of the iron pipe?
wlad13 [49]

Answer:

Mass=2549.784 \ g

Explanation:

The equation for mass is:

Mass = Density * Volume

We plug in the given values into the equation:

Mass = 7.86 \ g/mL * 324.4 \ mL

Mass=2549.784 \ g

6 0
2 years ago
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