How many moles of AlCl3 are in 2.25L of a 0.15 molar solution?

Chemistry

1 answer:

Darya [45]3 years ago

5 0

Answer:

Option C. 0.34 moles

Explanation:

Data obtained from the question include:

Molarity = 0.15M

Volume = 2.25L

Mole =

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.15 x 2.25

Mole = 0.34mole

The number of mole of AlCl3 present in the solution is 0.34mole.

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Explanation:

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First, we should find the mole of KOH:
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Now, let's find the volume of HNO3 soln:
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