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Serjik [45]
3 years ago
15

What is the mass (in grams) of 9.42 × 1024 molecules of methanol (CH3OH)?

Chemistry
2 answers:
Furkat [3]3 years ago
8 0
(9.42x10^24)/(6.02x10^23)=15.6478 mol methanol
15.6478mol(32.04g/1 mol)=501.3568g methanol
Sloan [31]3 years ago
6 0

Answer: 500 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text {avogadro's number}}=\frac{9.42\times10^{24}}{6.023\times 10^{23}}=15.6moles

1 mole of CH_3OH weighs = 32.04 g/mol

Thus 15.6 moles of CH_3OH weigh=\frac{32.04}{1}\times 15.6=500g

Thus the mass of 9.42\times10^{24} molecules of methanol is 500 grams

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Alchen [17]
What types of atoms typically form covalent bonds?

The correct answer:

d) Nonmetals with nonmetals, because their difference in electronegativity is below 1.7.

En example to explain:
An example of a covalent bonding: HCl -> 2 nonmentals
-> a difference in electronegativity less than 1.7:

EN(Cl) = 3.0 and EN (H) = 2.1 (you can search these values in a periodic table)
/\EN = 3.0 - 2.1 = 0.9

0.9 < 1.7

I hope this helped you out!
4 0
3 years ago
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Answer:

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5 0
3 years ago
What is the difference in mean solar time between 30 N 75 W and 30 N 90 W​
ratelena [41]

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Every 15 degrees is an hour

Explanation:

What is the time difference in mean solar time between 30° N 75° W and 30° N 90° W?

5 0
3 years ago
What is the mass of 2.80 grams of H2O
IrinaK [193]

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8 0
3 years ago
In a sulphuric acid (h2so4) - sodium hydroxide (naoh) acid-base titration, 17.3 ml of 0.126 m naoh is needed to neutralize 25 ml
katen-ka-za [31]
The balanced equation for the neutralisation reaction is as follows
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
the number of moles of NaOH reacted  - 0.126 mol/L  x 0.0173 L = 0.00218 mol
if 2 mol of NaOH reacts with 1 mol of H₂SO₄ 
then 0.00218 mol of NaOH reacts with - 0.00218 / 2 = 0.00109 mol of H₂SO₄ 
molarity is the number of moles of solute in 1 L solution
therefore if 25 mL contains - 0.00109 mol 
then 1000 mL contains - 0.00109 mol / 25 mL  x 1000 mL = 0.0436 mol/L
therefore molarity of H₂SO₄ is 0.0436 M
4 0
3 years ago
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