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oee [108]
3 years ago
9

A geologist wants to find out more about a new discovery in his field. What type of source should he consult?

Chemistry
2 answers:
Juli2301 [7.4K]3 years ago
6 0

The answer is c secondary source because it explains the experiment

cluponka [151]3 years ago
6 0

Answer:

<u><em>The answer is</em></u>: <u>C. A secondary source, because it explains the experiment.</u>

<u />

Explanation:

The primary sources<em> contain new and original information, the result of intellectual work. </em>

Secondary sources <em>contain organized, elaborated information, product of analysis, extraction or reorganization that refers to original primary documents. </em>

<u><em>The answer is</em></u>: <u>C. A secondary source, because it explains the experiment.</u>

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Which is a reactant in the cellular respiration reaction
Alexxandr [17]

Answer: Oxygen and glucose are both reactants in the process of cellular respiration.

Explanation: Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.

7 0
3 years ago
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A 0.2436-g sample of an unknown substance was dissolved in 20.0 ml of cyclohexane. The density of cyclohexane is 0.779 g/ml. The
Viktor [21]

The depression in freezing point is related to molality of solution as follows:

\Delta T_{f}=k_{f}m

Here, k_{f} is freezing point depression constant, for cyclohexane it is equal to 20°C kg/mol.

The value of freezing-point depression is 2.5 °C, molality can be calculated as follows:

m=\frac{\Delta T_{f}}{k_{f}}=\frac{2.5 ^{o}C}{20 ^{o}C kg/mol}=0.125 mol/kg

Molality is defined as number of moles of solute in 1 kg of solvent.

Here, solvent is cyclohexane, its volume is given 20.0 mL and density is 0.779 g/mol thus, mass of cyclohexane can be calculated as follows:

m=d\times V=0.779 g/mL\times 20 mL=15.58 g

Converting this into kg,

1 g=10^{-3} kg

Thus, 15.58 g will be 0.01558 kg.

Now, number of moles of unknown solute is related to its mass and molar mass as follows:

n=\frac{m}{M}

Putting the values of mass of solute which is 0.2436 or 0.0002436 kg

n=\frac{ 0.0002436 kg}{M}

Now, expression for molality of solution is:

m=\frac{n_{solute}}{m_{solvent}}

Putting all the values,

0.125 mol/kg=\frac{0.0002436 kg}{M\times 0.01558 kg}

Or,

0.125 mol/kg=\frac{0.015635}{M}

On rearranging,

M=\frac{0.015635}{0.125 mol/kg}=0.1250 kg/mol

Or,

M=0.125 kg/mol(\frac{1000 g}{1 kg})=125 g/mol

Therefore, molar mass of unknown sample is 125 g/mol

5 0
4 years ago
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GuDViN [60]
Steam.A pure substance has an unchanging composition,water in the form of steam has an unchanging composition

7 0
3 years ago
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liraira [26]

Answer:

4. C2H4, C3H6, C4H8

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Their general formula is CnH2n

you can check this fits for all these compounds

put n = 1, 2, 3 and so on

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Does spring and Fall exist at the poles?
seropon [69]

Answer:

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