Answer:
B. 1.65 L
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇒ 2 SO₃(g)
Step 2: Calculate the moles of SO₂
The pressure of the gas is 1.20 atm and the temperature 25 °C (298 K). We can calculate the moles using the ideal gas equation.
P × V = n × R × T
n = P × V / R × T
n = 1.20 atm × 1.50 L / (0.0821 atm.L/mol.K) × 298 K = 0.0736 mol
Step 3: Calculate the moles of SO₃ produced
0.0736 mol SO₂ × 2 mol SO₃/2 mol SO₂ = 0.0736 mol SO₃
Step 4: Calculate the volume occupied by 0.0736 moles of SO₃ at STP
At STP, 1 mole of an ideal gas occupies 22.4 L.
0.0736 mol × 22.4 L/1 mol = 1.65 L
<u>Answer:</u> The conjugate acid of 
is 
<u>Explanation:</u>
According to the Bronsted-Lowry conjugate acid-base theory:
- An acid is defined as a substance which looses donates protons and thus forming conjugate base.
- A base is defined as a substance which accepts protons and thus forming conjugate acid.
To form a conjugate acid of , this compound will accept one proton to form
The chemical equation for the formation of conjugate acid follows:
The conjugate acid formed is named as carbonic acid.
Hence, the conjugate acid of is
Answer:
4725.6 g of (NH4)2SO4
Explanation:
Molar mass of a substance is the number of mass of the substance contained in one mole of the substance. It is also called the formula weight of the compound. The formula mass of (NH4)2SO4 is 132 g/mol Hence;
Now we know that;
1 mole of (NH4)2SO4 contains 132 g of (NH4)2SO4
35.8 moles of (NH4)2SO4 contains 35.8 * 132/1
= 4725.6 g of (NH4)2SO4
1 x 10^18 picograms
I hope it helps you
That would be choice A.
Protons and Neutrons.
