The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:
a) 0.3277
b) 0.0128
Step-by-step explanation:
We are given the following information in the question:
N(2750, 560).
Mean, μ = 2750
Standard Deviation, σ = 560
We are given that the distribution of distribution of birth weights is a bell shaped distribution that is a normal distribution.
Formula:
a) P (less than 2500 grams)
P(x < 2500)
Calculation the value from standard normal z table, we have,
b) P ((less than 1500 grams)
P(x < 1500)
Calculation the value from standard normal z table, we have,
Answer:
Step-by-step explanation:
To make a guess as to the volume, it may be easier to guess in cups rather than centimeters or inches. One may visualize that a 12 ounce soda can is about 1.5 cups. This is equivalent to 354.88 cubic centimeters or 21.656 cubic inches.
3 times 24 is 48% therefore its D.
Answer: +/- 7
Step-by-step explanation:
3x² = 147
To solve for x divide through by three first.
3x² = 147
x² = 49, now we take the square root of both side by trying to apply laws of indices.
√x² = √49
The square root will neutralize the effect of the square because
√a = a¹/² so (x²)¹/², and (x²)¹/² =
x²×¹/² = x, therefore the solution is
x = +/- 7.
