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BaLLatris [955]
3 years ago
14

Tracy would like to buy a mountain bike with an original price of $935.11. Which coupon should she use 550.00 off or 60% off hel

p asap i will give 10 ptn
Mathematics
2 answers:
Angelina_Jolie [31]3 years ago
8 0
60% coupon is the correct answer - her total would amount to 374.04 while with the $550 would amount 385.11
Lapatulllka [165]3 years ago
5 0

Answer:

60% off

Step-by-step explanation:

Let's try both.

1. 550 off =

  935.11 - 550 = $385.11

2. 60% off =

   935.11 - (.60*935.11) = $374.04

$385.11 > $374.04, so she should use the 60% off coupon.

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a preschool student finds a big bag of cookies and begins to take the cookies from the bag and hide them in her cubbyhole. after
guajiro [1.7K]

Answer:She will count the cookies by 2's

Step-by-step explanation:

6 0
2 years ago
A florist has an order to make flower bouquets. the order calls for the use of 45 roses and 63 carnations. each bouquet made wil
Marta_Voda [28]
Find the GCF of both numbers
45-1,3,5,9,15,45
63-1,3,7,9,21,63
So each bouquet would have 9 of both rose and carnations
6 0
3 years ago
Find the mode of the following data set.
ivolga24 [154]
The mode is the number that shows up the most.

In the dataset, note that the stem should be in the tens place, and the different number of leaves are in the ones place.

62 shows up one more time than all the other numbers, and so 62 is your answer.


Hope this helps
8 0
3 years ago
Read 2 more answers
Inverse of y=14x2 show derivations
Rudik [331]
<h2>Answer:</h2>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

y=14x^2

<h3>2. Substitute y for x, and x for y.</h3>

x=14y^{2}

<h3>3. Solve for y.</h3>

14y^{2}=x\\ \\y^{2} =\frac{x}{14} \\ \\y=\sqrt{\frac{x}{14}}

<h3>4. Express your result.</h3>

f^{-1}  (x)=\sqrt{\frac{x}{14}}.

4 0
1 year ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
Read 2 more answers
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