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fenix001 [56]
3 years ago
5

Help please! This is super urgent!!!!!

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0
Cos^2x. hope this clarifies
const2013 [10]3 years ago
5 0
Important relationships to note:

sec(x) = 1/cos(x)
cot(x) = 1/tan(x)
cosec(x) = 1/sin(x)

Thus, we can say:
sec(x) · tan(x) · sin(x) = [sin(x) · tan(x)]/cos(x)
= tan(x) tan(x)
= tan^2(x)
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12 Feet is the depth of the pond.  I am just guessing but i think that is it.
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Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Which shows the correct substitution of the
Artemon [7]

Answer:

StartFraction 2 plus or minus StartRoot (negative 2) squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction

Step-by-step explanation:

General quadratic equation: ax^2 + bx + c

where a is the coefficient of the quadratic term, b is the coefficient of the linear term and c is the independent term. Here the equation is: x^2 – 2x – 3, so a = 1, b = -2 and c = -3

Quadratic formula:

x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}

Replacing

x = \frac{2 \pm \sqrt{(-2)^2-4(1)(-3)}}{2(1)}

8 0
3 years ago
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What is the slope of y = -x + 7
LenKa [72]
The slope of this equation would be m = -1
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3 years ago
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Find the constant of proportionality k. Then write an equation for the relationship between x and y.
egoroff_w [7]

Answer:

k= 5

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3 0
3 years ago
Can someone help me on this please :) ​
VashaNatasha [74]

9514 1404 393

Answer:

  • x = 6
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Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

__

  \left(\dfrac{a^3b^4}{a^2b}\right)^6= (a^{3-2}b^{4-1})^6 =a^{1\cdot6}b^{3\cdot6}=\boxed{a^6b^{18}}

Comparing to the given form, we see x=6, y=18.

4 0
3 years ago
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