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fenix001 [56]
3 years ago
5

Help please! This is super urgent!!!!!

Mathematics
2 answers:
a_sh-v [17]3 years ago
7 0
Cos^2x. hope this clarifies
const2013 [10]3 years ago
5 0
Important relationships to note:

sec(x) = 1/cos(x)
cot(x) = 1/tan(x)
cosec(x) = 1/sin(x)

Thus, we can say:
sec(x) · tan(x) · sin(x) = [sin(x) · tan(x)]/cos(x)
= tan(x) tan(x)
= tan^2(x)
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Solve. What is 99×89-34÷2-1?
Slav-nsk [51]

Answer:

8793

Step-by-step explanation:

Multiply and divide first, making the equation 8811-17-1. Now subtract. This leaves 8793

7 0
3 years ago
Read 2 more answers
Joshua has a ladder that is 15 feet long. He wants to lean the ladder against a vertical wall so that the top of the ladder is 1
Lyrx [107]

Answer:



Step-by-step explanation:

4 0
2 years ago
What kind of solution(s) do you expect for the linear equation:
Kryger [21]
One solution A. Thats the correct answer
7 0
3 years ago
#2 <br> #3 <br> Need help for my discrete math class
miss Akunina [59]

For (2), start with the base case. When n = 2, we have

(n + 1)! = (2 + 1)! = 3! = 6

2ⁿ = 2² = 4

6 > 4, so the case of n = 2 is true.

Now assume the inequality holds for n = k, so that

(k + 1)! > 2ᵏ

Under this hypothesis, we want to show the inequality holds for n = k + 1. By definition of factorial, we have

((k + 1) + 1)! = (k + 2)! = (k + 2) (k + 1)!

Then by our hypothesis,

(k + 2) (k + 1)! > (k + 2) 2ᵏ = k•2ᵏ + 2ᵏ⁺¹

and k•2ᵏ ≥ 2•2² = 8, so

k•2ᵏ + 2ᵏ⁺¹ ≥ 8 + 2ᵏ⁺¹ > 2ᵏ⁺¹

which proves the claim.

Unfortunately, I can't help you with (3). Sorry!

3 0
3 years ago
A factory produces 80 % round and 20 % square buttons. Suppose that 10 % of theround buttons and 50 % of the square buttons are
Katarina [22]

Answer:

5/9

Step-by-step explanation:

Let the total number of buttons is x.

  • Round buttons = 80% of x = 0.8x
  • Square buttons = 0.2x

<u>Number of red buttons:</u>

  • 0.1*0.8x + 0.5*0.2x =
  • 0.08x + 0.1x =
  • 0.18x

Number of red square buttons is 0.1x

<u>Required probability:</u>

  • P = 0.1x/0.18x = 10/18 = 5/9
4 0
3 years ago
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