<h2>Option A is the correct answer.</h2>
Explanation:
Here we need to find an expression that would yield a value for time⁻¹
We know that
Velocity = Displacement ÷ Time
v = x/t
Option A :
Option A is correct
Option B :
Option B is not correct
Option C :
Option C is not correct
Option D :
Option D is not correct
Option E :
Option E is not correct
Option A is the correct answer.
Please,,,,,,,,,,,,,,,,,,,
Airida [17]
Answer:
bsjzbzkzznnzkzkznzjzbzbzbzbzbzbzbzbznznenenenenenene
Answer:
Explanation:
A ) When gymnast is motionless , he is in equilibrium
T = mg
= 63 x 9.81
= 618.03 N
B )
When gymnast climbs up at a constant rate , he is still in equilibrium ie net force acting on it is zero as acceleration is zero.
T = mg
= 618.03 N
C ) If the gymnast climbs up the rope with an upward acceleration of magnitude 0.600 m/s2
Net force on it = T - mg , acting in upward direction
T - mg = m a
T = mg + m a
= m ( g + a )
= 63 ( 9.81 + .6)
= 655.83 N
D ) If the gymnast slides down the rope with a downward acceleration of magnitude 0.600 m/s2
Net force acting in downward direction
mg - T = ma
T = m ( g - a )
= 63 x ( 9.81 - .6 )
= 580.23 N
Answer:
<em>7.45 10^5N.</em>
Explanation:
according to newtons second law of motion;
Fapp is the applied force
Fr is the resistive force
m is the mass of the luxury
a is the acceleration
Since the huge luxury liner move with constant velocity, then acceleration is zero i.e a = 0. The equation becomes;
This shows that the applied force will be equal to the resistive force if the velocity is constant.
Given Fr = 7.45 10^5 N therefore the resistive force will also be 7.45 10^5N.
<em>Hence the magnitude of the resistive force exerted by the water on the cruise ship is 7.45 10^5N.</em>
Power = current x voltage
So the power is 7 x 110 = 770 W = 0.77kW
0.77 x 13 = 10.01 kWh
10.01 x 10 cents = 100.1 cents (is this 1 dollar? Idk I use a different currency)