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Sphinxa [80]
3 years ago
11

A person kicks a ball off of a 50m high cliff with a speed of 10 m/s. How long will it take the ball to hit the ground? * 7 poin

ts 2.3 sec 6.3 sec 4.5 sec 3.2 sec
Physics
1 answer:
Musya8 [376]3 years ago
6 0

Presumably, the ball is kicked parallel to the ground below the cliff, so its altitude <em>y</em> at time <em>t</em> is

y(t)=50\,\mathrm m-\dfrac12gt^2

where <em>g</em> = 9.80 m/s^2 is the acceleration due to gravity.

The ball hits the ground when <em>y</em> = 0:

0 = 50\,\mathrm m-\dfrac12gt^2

t^2=\dfrac{100\,\mathrm m}g

t=\dfrac{10}{9.80}\,\mathrm s\approx\boxed{3.2\,\mathrm s}

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 x =  0.176 m

Explanation:

For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.

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