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aev [14]
3 years ago
5

Need help will mark Brainliest no explanation needed

Mathematics
1 answer:
STatiana [176]3 years ago
8 0
I can’t see the whole problem but The triangle is SAS and it it is translated
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11. You are asked to put a V-shaped roof on a house. The slope of the roof is 53°. What is the measure of the angle needed at th
Anestetic [448]
The question said that it told you the base angles. A roof would have two equal base angles. The base angles= 53

All the angles of a triangle each 180, (the roof is shaped like a triangle)

So, let's make x the missing angle.

53(2)+x=180

106+x=180

Subtract 106 on both sides.

180-106= 74

The vertex angle is 74.

I hope this helps!
~cupcake
4 0
3 years ago
Read 2 more answers
Cole paid $24 for 2 calculators and a pack of pens. Kai paid $45 for 3 calculators and 2 packs of pens. They both paid $6 for ea
s344n2d4d5 [400]
$12 for one of the calculators
3 0
3 years ago
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I REALLY NEED HELP WORTH 10 POINTS URGENT!!!!!
polet [3.4K]

Answer:

(f\circ g)(4)=31

Step-by-step explanation:

<u>Composite Function</u>

Given f(x) and g(x) real functions, the composite function named fog(x) is defined as:

(f\circ g)(x)=f(g(x))

For practical purposes, it can be found by substituting g into f.

We have:

f(x)=3x+1

g(x)=x^2-6

Computing the composite function:

(f\circ g)(x)=f(g(x))=3(x^2-6)+1

Operating:

(f\circ g)(x)=3x^2-18+1

Operating:

(f\circ g)(x)=3x^2-17

Now evaluate for x=4

(f\circ g)(4)=3(4)^2-17=48-17

\boxed{(f\circ g)(4)=31}

8 0
3 years ago
Identify an equation in point-slope form for the line parallel to y = 3x-7 that
Zigmanuir [339]

Answer:The equation of the line parallel to (3x - y = 7) passes through the point (-5, -3) is y = 3x + 2 and this can be determined by using the one-point slope form.

8 0
2 years ago
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For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
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