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3 years ago

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What is 348,000,000,000,000 estimated as the product of a single digit and a power of 10? NOTE: This is a question regarding sci

entific notation.

2 answers:

mrs_skeptik [129]3 years ago

4 0

$The\ scientific\ notation:a\cdot10^n\ where\ 1\leq a \ \textless \ 10\ and\ n\in\mathbb{Z}.\\\\384,000,000,000,000=3.84\cdot10^{14}$

Lelechka [254]3 years ago

4 0

The answer is 3.48 * 10^14.

For an elementary way of solving for the exponent of 10, you may begin to count from the rightmost digit until the decimal point is between 3 and 8. You will notice you have passed by 14 digits. Thus, <span>3.48 * 10^14.

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Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

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find the coordinates of the circumcenter of triangle abc. A(0,5) B(-4,5) C(-4,-3) PLEASE HELP IM FAILING AND I WILL GIVE BRAINLI

hodyreva [135]

(-2,1). Hope this helps!

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3 years ago

30 tens = ones<br> 30 tens = hundreds

Svetllana [295]

30 tens = 30 x 10 = 300

300 ones = 300 x 1 = 300

300 is your answer

30 tens = 30 x 10 = 300

3 hundreds = 3 x 100 = 300

3 is your answer

<em>~Rise Above the Ordinary</em>

4 0

3 years ago

A cone shaped paper water cup has a height of 12 cm and a radius of 6 cm. If the cup is filled with water to half its height, wh

monitta

Answer:

The portion of the volume of the cup that is filled with water is $\frac{1}{8}$

Step-by-step explanation:

step 1

Find the volume of the paper water cup

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

we have

$r=6\ cm$

$h=12\ cm$

substitute

$V=\frac{1}{3}\pi (6)^{2}(12)$

$V=144\pi\ cm^{3}$

step 2

If the cup is filled with water to half its height, find out what portion of the volume of the cup is filled with water

Remember that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

In this problem the similar cone has half the height of the complete cone

so

The scale factor is equal to 1/2

therefore

The volume of the cup that is filled with water is equal to the volume of the complete cup by the scale factor elevated to the cube

$V=(1/2)^{3}(144\pi)=(1/8)144\pi\ cm^{3}$

therefore

The portion of the volume of the cup that is filled with water is

$\frac{1}{8}$

8 0

3 years ago

Read 2 more answers

WHAT IS THE SLOPE PLEASE??

strojnjashka [21]

Answer:

Step-by-step explanation:

take two points on the line ,i take (-4,0) and (0,-2)

slope=(y2-y1)/(x2-x1)=(-2-0)/(0+4)=-2/4=-1/2

6 0

3 years ago

Read 2 more answers

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with σ=0.0

oksian1 [2.3K]

<h2>Answer with explanation:</h2>

The confidence interval for population mean is given by :-

$\overline{x}\pm z^* SE$ (1)

, where $\overline{x}$ = sample mean

z* = critical value.

SE = standard error

and $SE=\dfrac{\sigma}{\sqrt{n}}$ , $\sigma$ = population standard deviation.

n= sample size.

As per given , we have

$\overline{x}=74.021$

$\sigma=0.001$

n= 15

It is known that ring diameter is normally distributed.

$SE=\dfrac{0.001}{\sqrt{15}}=0.000258198889747\approx0.000258199$

By z-table ,

The critical value for 95% confidence = z*= 1.96

A 99% two-sided confidence interval on the true mean piston diameter :

$74.021\pm (2.576) (0.000258199)$ (using (1))

$74.021\pm 0.000665120624$

$74.021\pm 0.000665120624\\\\=(74.021- 0.000665120624,\ 74.021+ 0.000665120624)\\\\=(74.0203348794,\ 74.0216651206)\approx(74.020,\ 74.022)$ [Rounded to three decimal places]

∴ A 99% two-sided confidence interval on the true mean piston diameter = (74.020, 74.022)

By z-table ,

The critical value for 95% confidence = z*= 1.96

A 95% lower confidence bound on the true mean piston diameter:

$74.021- (1.96) (0.000258199)$ (using (1))

$74.021- 0.00050607004=74.02049393\approx74.020$ [Rounded to three decimal places]

∴ A 95% lower confidence bound on the true mean piston diameter= 74.020

7 0

3 years ago