A rectangular park is 56 mi wide and 157 mi long.

Write and solve the equation and then check your answer.

sweet-ann [11.9K]

Answer:

- The correct equation is 6s = 7.80

- The solution of the equation is s = $1.30

Step-by-step explanation:

To find the product of 6 and a number, first we denote the unknown number as s.

The product of 6 and s is the same as 6s.

If the product of both numbers is $7.80, then 6s = $7.80

The correct equation is therefore 6s = $7.80

To get the value of s, we will divide both sides by 6 to have:

6s/6 = $7.80/6

s = $1.30

Based on the calculation, the following statements are true

- The correct equation is 6s = 7.80

- The solution of the equation is s = $1.30

8 0

3 years ago

Read 2 more answers

Consider a circle whose equation is x2 + y2 + 4x – 6y – 36 = 0. Which statements are true? Check all that apply. To begin conver

umka21 [38]

Answer:

1) False, to begin converting the equation to standard form, each side must be added by 36. 2) True, to complete the square for the x terms, add 4 to both sides, 3) True, the center of the circle is at (-2, 3), 4) False, the center of the circle is at (-2, 3), 5) False, the radius of the circle is 7 units, 6) False, the radius of the circle is 7 units.

Step-by-step explanation:

Let prove the validity of each choice:

1) To begin converting the equation to standard form, subtract 36 from both sides:

Let consider the following formula and perform the following algebraic operations:

(i) $x^{2} + y^{2} + 4\cdot x - 6\cdot y - 36 = 0$ Given

(ii) $x^{2} + 4\cdot x + y^{2} - 6\cdot y - 36 = 0$ Commutative Property

(iii) $(x^{2} + 4\cdot x + 4) - 4 + (y^{2} - 6\cdot y + 9) - 9 -36 = 0$ Modulative/Associative Property/Additive Inverse Existence

(iv) $(x+ 2)^{2} - 4 + (y - 3)^{2} - 9 - 36 = 0$ Perfect Trinomial Square

(v) $(x+2)^{2} +(y-3)^{2} = 4 + 9 + 36$ Commutative Property/Compatibility with Addition/Additive Inverse Existence/Modulative Property

(vi) $(x+2)^{2} + (y-3)^{2} = 49$ Definition of Addition/Result

False, to begin converting the equation to standard form, each side must be added by 36.

2) True, step (iii) on exercise 1) indicates that both side must be added by 4.

3) The general equation for a circle centered at (h, k) is of the form:

$(x-h)^{2}+ (y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle.

By direct comparison, it is evident that circle is centered at (-2,3).

True, step (vi) on exercise 1) indicates that center of the circle is at (-2, 3).

4) False, step (vi) on exercise 1) indicates that the center of the circle is at (-2, 3), not in (4, -6).

5) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

6) After comparing both formulas, it is evident that radius of the circle is 7 units.

False, the radius of the circle is 7 units.

5 0

3 years ago

Read 2 more answers

What is 67+9,000???? a. 67,679 b. 9,067 c. 67,980

Mashutka [201]

The answers is B. 9,067

7 0

3 years ago

Read 2 more answers

The point R(-3,a,-1) is the midpoint of the line segment jointing the points P(1,2,b)

wlad13 [49]

Answer:

The values are:

$a = -5/2$

$b = -6$

$c = -7$

Step-by-step explanation:

Given:

P = (x₁, y₁, z₁) = (1, 2, b)

Q = (x₂, y₂, z₂) = (c, -7, 4)

m = R = (x, y, z) = (-3, a, -1)

To Determine:

a = ?

b = ?

c = ?

Determining the values of a, b, and c

Using the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

As the point R(-3, a, -1) is the midpoint of the line segment jointing the points P(1,2,b) and Q(c,-7,4), so

m = R = (x, y, z) = (-3, a, -1)

Using the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

given

(x₁, y₁, z₁) = (1, 2, b) = P

(x₂, y₂, z₂) = (c, -7, 4) = Q

m = (x, y, z) = (-3, a, -1) = R

substituting the value of (x₁, y₁, z₁) = (1, 2, b) = P, (x₂, y₂, z₂) = (c, -7, 4) = Q, and m = (x, y, z) = (-3, a, -1) = R in the mid-point formula

$m\:=\:\left(\frac{x_1+x_2}{2},\:\frac{y_1+y_2}{2},\:\frac{z_1+z_2}{2}\right)$

$\left(x,\:y,\:z\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)$

as (x, y, z) = (-3, a, -1), so

$\left(-3,\:a,\:-1\right)\:=\:\left(\frac{1+c}{2},\:\frac{2+\left(-7\right)}{2},\:\frac{b+4}{2}\right)$

Determining 'c'

-3 = (1+c) / (2)

-3 × 2 = 1+c

$1+c = -6$

$c = -6 - 1$

$c = -7$

Determining 'a'

a = (2+(-7)) / 2

$2a = 2-7$

$2a = -5$

$a = -5/2$

Determining 'b'

-1 = (b+4) / 2

$-2 = b+4$

$b = -2-4$

$b = -6$

Therefore, the values are:

$a = -5/2$

$b = -6$

$c = -7$

6 0

3 years ago

You draw two cards at random from a standard deck. What is the probability of drawing at least one diamond?

hodyreva [135]

Well there are 52 cards in a deck. There are 13 of each kind of card. So 13/52 are diamonds

7 0

3 years ago