For dividing fractions you should always use the KCF method: Keep Change Flip
6/10 divided by 12/7
Kcf method:
6/10*7/12= 42/120
42/120 in simplest form will be 7/20
So the answer is A
The answer to this problem is (x,y) = (-4,2)
Given that

, we have for

the Taylor series expansion about 0 as
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Replace

with

, so that the series is equivalent to

and notice that

Recall that for

, we have

which means

A.
1.84
will be the answer