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GenaCL600 [577]
3 years ago
9

Evaluate. [42 ÷ (2 + 3 • 2)] + [4 • (36 – 52)] I really need help!!!

Mathematics
1 answer:
juin [17]3 years ago
8 0
Ok so first we do 2 + 3 = 5 * 2 = 10 / by 42 = 4.2

other side 36 - 52 = 16 * 4 = 64 now add     4.2 + 64 = 68.2
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What is the equation for the model?
gayaneshka [121]
B five x equal to 4
8 0
3 years ago
Find sin theta if theta is an angle in standard position and the point with coordinates (3, -4) lies on the terminal side of an
alisha [4.7K]

Answer:

\sin \theta=-\frac{4}{5}

Step-by-step explanation:

Given:

Angle is in standard position which means the starting ray is at the origin. The terminal side has coordinates (3, -4).

So, the 'x' value is 3 and 'y' value id -4.

Using Pythagoras Theorem, we find the hypotenuse.

Hypotenuse = \sqrt{3^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5

Now, using the sine ratio for the angle, we have

\sin \theta=\frac{Opposite}{Hypotenuse}\\\sin \theta=\frac{-4}{5}\\\sin \theta=-\frac{4}{5}

Therefore, the value of \sin \theta is -\frac{4}{5}.

The value is negative as the point (3, -4) lies in the fourth quadrant and sine ratio is negative in the fourth quadrant,

4 0
3 years ago
Recall, we have five connectives in propositional logic ¬, ∧, ∨, →, ↔ (negation, conjunction, disjunction, conditional and bicon
Free_Kalibri [48]

Answer:

(a) ¬(p→¬q)

(b) ¬p→q

(c) ¬((p→q)→¬(q→p))

Step-by-step explanation

taking into account the truth table for the conditional connective:

<u>p | q | p→q </u>

T | T |   T    

T | F |   F    

F | T |   T    

F | F |   T    

(a) and (b) can be seen from truth tables:

for (a) <u>p∧q</u>:

<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>

T | T |  F  |   F     |    T       |  T

T | F |  T  |  T      |    F       |  F

F | T |  F  |  T      |    F       |  F

F | F |  T  |  T      |    F       |  F

As they have the same truth table, they are equivalent.

In a similar manner, for (b) p∨q:

<u>p | q | ¬p | ¬p→q | p∨q</u>

T | T |  F  |   T     |    T    

T | F |  F  |   T     |    T    

F | T |  T  |   T     |    T    

F | F |  T  |   F     |    F    

again, the truth tables are the same.

For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))

4 0
3 years ago
The figures below are rectangles. Which polynomial represents the area of the shaded region? HAVE ALL MY POINTS but answer truth
Aleks04 [339]

Answer:

7x - 1

Step-by-step explanation:

Area of the shaded region = area of the large rectangular - area of the small rectangle

Area of rectangle is given as l*w

Area of the large rectangle = l*w = (x + 5)(x - 1)

Expand

= x(x - 1) +5(x - 1)

= x^2 - x + 5x - 5

Area of large rectangle = x^2 + 4x - 5

Area of small rectangle = l*w = (x + 1)(x - 4)

= x(x - 4) +1(x - 4)

=  x^2 - 4x + x - 4

Area of small rectangle = =  x^2 - 3x - 4

Area of shaded region = (x^2 + 4x - 5) - (x^2 - 3x - 4)

= x^2 + 4x - 5 - x^2 + 3x + 4

Collect like terms

= x^2 - x^2 + 4x + 3x - 5 + 4

= 7x - 1

6 0
3 years ago
What is the discriminant of the quadratic equation 0 = –x2 + 4x – 2?
kvv77 [185]
0=-x2+4x-2
+x2-4x+2=+x2-4x+2
___________________
x2-4x+2=0

(-4)^2-4(1)(2)

16-8

Final Answer: 8

3 0
3 years ago
Read 2 more answers
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