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Arisa [49]
3 years ago
11

How many milliliters of 0.45 m hcl will neutralize 25.0 ml of 1.00 m koh?

Chemistry
2 answers:
emmasim [6.3K]3 years ago
5 0
Approx. <span>60⋅mL</span><span> of hydrochloric acid are required.</span>
dimaraw [331]3 years ago
3 0

Answer:

55.55 mL of HCl 0.45 m are needed to neutralize 25 mL of 1 m KOH

Explanation:

The equation that describes the reaction is:

HCl + KOH = KCl + H_{2} O

We can see that one mole of HCl is needed to consume one mole of KOH

Looking at the units:

0.45 m HCl = \frac{0.45 MOL HCl}{Liter} \\1 m KOH = \frac{1 MOL KOH}{Liter}

So, kepping in mind the previous statements, we proceed to calculate the total moles of KOH in the solution:

Now we know that we need 0.025 MOL of HCl to neutralize the solution; So:

\frac{0.45 MOL HCl}{1 Liter} *\frac{1 Liter}{1000mLiters}=\frac{0.00045 MOL}{1mLiter}

\frac{0.025 MOL KOH}{\frac{0.00045 MOL HCL}{1mLiter} } = 55.5556 mLiters

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