The table with the data is in the picture attached.
Answer:
Explanation:
The reaction equation suggests that the law could have this form:
Then, the work is to find the values of the exponents that satisfy the initial rate data.
A first glance shows that for the third and fourth trials the initial rates are the same. Since for these two trials only the initial concentration of substance B changed (A and C were kept equal), you conclude that the reaction rate does not depend on B, and ist exponent (lower b) is 0.
Then, so far you can say:
When you use trials 1 and 2, you get:
Now, you can use trials 1 and 3 to determine the other exponent:
Thus, you have the rate law:
Now, you just use any trial to obtain k. Using trail 1:
Which yields:
Reaction type : Double-Replacement reactions
<h3>Further explanation</h3>
Given
Reaction
MgCl2 +
Li2CO3 →
MgCO3 +
LiCl
Required
Balanced equation
Reaction type
Solution
Balanced equation
Li2CO3 (s) + MgCl2 (aq) → MgCO3 (s) + 2 LiCl (aq)
Double-Replacement reactions. Happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
To predict whether this reaction can occur or not is one of them, the precipitation reaction.
MgCO3 is a precipitation compound
This problem is providing us with the mass (70 g), absorbed heat (96 J) and initial and final temperatures (293 K and 313 K, respectively) so the specific heat of the material is required and found to be 0.0686 J/(g*K) as shown below:
<h3>
Calorimetry:</h3>
In chemistry, we can go over calorimetry by writing the following relationship among heat, mass, specific heat and temperature change:
Thus, one can get the specific heat by solving for C in the previous equation:
Hence, we can plug in the given data to obtain:
Learn more about calorimetry: brainly.com/question/1407669
The more shielding, inner electrons
Answer:
Mass = 785.9 g
Explanation:
Given data:
Atoms of gold = 2.4 × 10²⁴ atoms
Mass of gold = ?
Solution:
First of all we will convert the number of atoms into moles.
2.4 × 10²⁴ atoms × 1 mol/ 6.02 × 10²³ atoms
number of moles = 3.99 mol
Now we will determine the mass of gold.
Mass = number of moles × molar mass
Mass = 3.99 mol × 196.97 g/mol
Mass = 785.9 g