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melisa1 [442]
3 years ago
15

How many moles are in a 501mL of a 2.37 M solution of Al2(SO4)3?

Chemistry
1 answer:
MissTica3 years ago
8 0

The number of moles of Al₂(SO₄)₃ is 1.2 mol

<u>Explanation:</u>

Given:

Volume of the solution, V = 501 mL

                                        V = 0.501L

Molarity of the solution, M = 2.37M

Moles, n = ?

We know:

Molarity = \frac{moles of solute}{volumeof solution}

On substituting the values we get:

2.37 = \frac{n}{0.501} \\\\n = 1.2 mol

Therefore, the number of moles of Al₂(SO₄)₃ is 1.2 mol

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The atomic mass of an element is the average of the atomic masses of its isotopes. The relative abundance of isotopes must be taken into consideration, therefore:
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We know:
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Thus:
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