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lana66690 [7]
3 years ago
12

Millikan's oil–drop experiment measures the charge on individual oil drops. Why would you try to set the electric field force on

a drop equal to the gravitational force on that drop? so that the oil drop moves randomly so that the oil drop moves downward so that the oil drop moves upward so that the oil drop remains suspended
Physics
2 answers:
IRISSAK [1]3 years ago
8 0
So that the oil drop stays suspended. 
at the point where it is stationary, its weight and the force on it due to the field are equal . so you can work out any detail you need
Ulleksa [173]3 years ago
5 0

Answer: so that the oil drop remains suspended

Explanation:

Millikan's oil  drop experiment was used to determine charge on electron. The charged oil droplets were suspended between electric field to balance the gravitational force and drag force.

The electric field is generated by applying potential difference across two parallel metal plates. The oil is sprayed which gets charged due to electric field. The field can be controlled by altering voltage difference across the plates. Oil drops reach terminal velocity when gravitational pull and drag force is balanced by the electric force.

The balance equation helps to find the charge on the oil droplet.

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Answer:

move upward with increasing speed

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4 years ago
A wildlife researcher is tracking a flock of geese. the geese fly 3.5 km due west, then turn toward the north by 40 ∘ and fly an
kaheart [24]

To solve this problem, we can use the cosine formula for calculating the length of the displacement:

c^2 = a^2 + b^2 – 2 a b cos θ

 

where c is the displacement, a = 3.5 km, b = 4.5 km, and θ is the angle inside the triangle

 

Since the geeze turned 40° from west to north, so the angle inside the triangle must be:

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c = 7.53 km

 

<span>So the magnitude of the displacement is 7.53 km</span>

4 0
3 years ago
Read 2 more answers
A student wants to demonstrate entropy using the songs on her portable
Salsk061 [2.6K]

Answer:

Explanation:

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8 0
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Scientists are told to doubt everything and not believe anything that is not provable. Is this a strength or weakness of science
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A very small object with mass 8.30×10-9 kg and positive charge 6.90×10-9 C is projected directly toward a very large insulating
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Answer:

41.4496148484\ m/s

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

\sigma = Surface charge density = 5.9\times 10^{-8}\ C/m^2

\Delta x = 0.57-0.26

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Electric field due to a sheet is given by

E=\dfrac{\sigma}{2\epsilon_0}\\\Rightarrow E=\dfrac{5.9\times 10^{-8}}{2\times 8.85\times 10^{-12}}\\\Rightarrow E=3333.33\ V/m

Electric field is given by

E=\dfrac{V}{d}

Voltage is given by

V=E\Delta x

Kinetic energy is given by

K=qV

\dfrac{1}{2}mv^2=qE\Delta x\\\Rightarrow v=\sqrt{\dfrac{2qE\Delta x}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 6.9\times 10^{-9}\times 3333.33\times (0.57-0.26)}{8.3\times 10^{-9}}}\\\Rightarrow v=41.4496148484\ m/s

The initial speed of the object is 41.4496148484\ m/s

7 0
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