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lana66690 [7]
3 years ago
12

Millikan's oil–drop experiment measures the charge on individual oil drops. Why would you try to set the electric field force on

a drop equal to the gravitational force on that drop? so that the oil drop moves randomly so that the oil drop moves downward so that the oil drop moves upward so that the oil drop remains suspended
Physics
2 answers:
IRISSAK [1]3 years ago
8 0
So that the oil drop stays suspended. 
at the point where it is stationary, its weight and the force on it due to the field are equal . so you can work out any detail you need
Ulleksa [173]3 years ago
5 0

Answer: so that the oil drop remains suspended

Explanation:

Millikan's oil  drop experiment was used to determine charge on electron. The charged oil droplets were suspended between electric field to balance the gravitational force and drag force.

The electric field is generated by applying potential difference across two parallel metal plates. The oil is sprayed which gets charged due to electric field. The field can be controlled by altering voltage difference across the plates. Oil drops reach terminal velocity when gravitational pull and drag force is balanced by the electric force.

The balance equation helps to find the charge on the oil droplet.

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4.
Nezavi [6.7K]

The density of an object remains same irrespective of its shape, size and quantity.

Explanation:

Density is an intensive property. This means that regardless of the object's shape, size, or quantity, the density of that substance will always be the same. Even if you cut the object into a million pieces, they would still each have the same density. It is because density in an intensive property of matter.

please mark brainliest

7 0
3 years ago
If the car were being moved sideways, could you determine the force on the car by using the weight equation
VashaNatasha [74]
No, if the car were moving sideways, then the forces used would be on the horizontal axis. So the weight equation would be extraneous, unless one is determining the net force through an inclined plane
7 0
3 years ago
A steel rod is pulled in tension along its center axis (the axial direction) with a stress that is less than the yield strength.
Kamila [148]

Answer:

D. Axial stress divided by axial strain

Explanation:

 Lets take rod is pulled by force P

Stress σ = P/A

We know that

σ = ε E

E=  Lets take rod is pulled by force P

Stress σ = P/A

We know that

σ = ε E

σ=Axial stress

ε  =Axial Strain = ΔL/L

E= σ/ε

E= Axial stress/Axial Strain

So the modulus of elasticity  is the ratio of axial stress to axial strain.

σ=Axial stress

ε  =Axial Strain = ΔL/L

E= σ/ε

E= Axial stress/Axial Strain

So the modulus of elasticity  is the ratio of axial stress to axial strain.

The option D is correct.

6 0
3 years ago
If 400g is 1kg find the ratio in the simplest form​
uranmaximum [27]

2:5

Explanation:

400g : 1kg

400g: 1000g

4 : 10

2 : 5

6 0
3 years ago
Another name for the water cycle is the​
atroni [7]

Answer:

<h2>Hydrologic cycle</h2>

Explanation:

Stay safe, stay healthy and blessed.

Have a good day !

Thank you

5 0
2 years ago
Read 2 more answers
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