Answer:
0.34 x 10^-3 m^3
Explanation:
P1 = 6 x 10^5 N/m^2
T1 = 10 degree C = 10 + 273 = 283 K
T2 = 35 degree c = 35 + 273 = 308 K
Pressure remains constant , P2 = P1
P1 V1 = R T1
V1 = (8.314 x 283) / (6 x 10^5) = 3.92 x 10^-3 m^3
Now, let the Volume is V2
P1 V2 = R T2
V2 = (8.314 x 308) / (6 x 10^5) = 4.26 x 10^-3 m^3
Change in volume, v = V2 - V1 = (4.26 - 3.92) x 10^-3 = 0.34 x 10^-3 m^3
How fine do you want them categorized for the ranking ?
What's the population to be ranked ?
The 4000 naked-eye-visible stars ?
The stars within, say, 50 light years from Earth ?
All 200-400 billion stars in the Milky Way galaxy ?
All the stars in some other galaxy ?
Or did you have a list of items to be ranked that you decided not to share ?
That would be a lot like asking us to seat a class of sixth graders alphabetically,
and then not telling us their names.
And how do we drag one star on top of another ?
And if I do that here, how will you know about it ?
Speed = Starting speed + (time + acceleration)
Starting speed is 0, acceleration is 2 m/s, speed is 30
30 = 0 + 2t
t ( stands for time ) = 15
As we know that when charge is released in electric field
It will have two forces on it
1. electrostatic force
2. gravitational force
now if the ball will accelerate upwards so we can say
net upward force = mass * acceleration
now we can find charge q on it by above equation
So above is the charge on the particle
Answer:
a camera employs camera lens to firm some images.
Explanation:
hope this helps.