To find the Chebyshev's inequality, P | Xn - E(X)| <= δ/4 >= 1 - (δ^2/25)/(δ^2/16) = 1 - (16/25) = 9/25 = 0.36
The answer in this question which is the probability that the average of the physicist's measurement is within δ/4 units of the actual specific gravity is at least 0.36%

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4 years ago

I really need help with this question. I have attached two screenshots, the first is the question and the second one is the opti

Sliva [168]

Using proportions, it is found that the coordinates of point B are given as follows:

A. (1.6, 0).

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

Point B is 3/4 of the way from AB to AC, hence:

$B - A = \frac{3}{4}(C - A)$

The points are:

A(-2,-3).

B(x,y).

C(3,1).

Then, to find the x-coordinate:

$x + 2 = \frac{3}{4}(3 + 2)$

x + 2 = 3.6.

x = 1.6.

For the y-coordinate:

$y + 3 = \frac{3}{4}(1 + 3)$

y + 3 = 3

y = 0.

Hence option A is correct.

More can be learned about proportions at brainly.com/question/24372153

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2 years ago