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cupoosta [38]
3 years ago
11

The place value of 2 in 5.32 is​

Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer: hundredths

Step-by-step explanation:

The second number past the decimal point is the hundredths place

Gelneren [198K]3 years ago
3 0
It is in the hundredths place hope this helps
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V +25 <5 And show work. PLZ HELP MEH I DONT KNOWWWWW
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Answer:

V+25<5

V<5-25

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V is less than -20

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A line has slope 5/6 an y-intercept -3 which answer is the equation of the line
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The answer is y=5/6x-3
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What is the cube if 8?
vlada-n [284]
The cube root of 8 is 2.
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Staci is attending a music festival. The ticket to the festival costs $87.96 . Staci plans to purchase $30.00 t-shirts form the
d1i1m1o1n [39]

Answer:

3 t-shirts

Step-by-step explanation:

<u>Lets recap the information we will use from this problem:</u>

The ticket to the festival costs $87.96

T-shirts are $30.00

She is taking $200.00 to the festival

Now we can solve. First we will subtract the price of the ticket from the total amount of money she has.

$200.00 - $87.96 = $112.04

Now that she has payed for the ticket, we want to find out how many shirts she can buy with the remainder of her money. To find this, we will set up an equation like this:

(Amount of money left) ÷ (Cost of 1 t-shirt) = (How many t-shirts she can buy)

Insert your numbers: $112.04 ÷ $30.00 = 3.73466666667

Because she cant buy a fraction of a t-shirt, we ignore the decimals on the end of this number. Therefore, Staci can purchase 3 t-shirts.

5 0
3 years ago
A box contains four $1 and six $5 bills. if three bills are selected at random without replacement, find the probability that al
myrzilka [38]

Answer:

C.1/6

Step-by-step explanation:

Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;

(number of $5 bills) / (total number of bills)

= (6)/(4+6) = 3/5

If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (5)/(4+5) = 5/9

The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.

Now, the probability of picking a $5 bill in the third attempt will be given as;

(new number of $5 bills) / (new total number of bills)

= (4)/(4+4) = 1/2

Since the three attempts are independent, the probability of picking  all three $5 bills is;

3/5 * 5/9 * 1/2 = 1/6

7 0
3 years ago
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